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nignag [31]
3 years ago
11

What would the answer to -|-24| be?

Mathematics
1 answer:
Anettt [7]3 years ago
4 0
-24 because the negative is outside the absolute value
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You randomly survey men and women about whether they plan to watch a football game on Sunday afternoon. A total of 40 men plan t
Alecsey [184]

Answer: 101

Step-by-step explanation:

45 women total

17 women will not watch the game

So 33 people did not want to watch the game and 17 are women

33-17 = 16 men who won’t watch the game

So 40 men who will and 16 men who won’t equals 56 men and 45 women

56+45= 101

5 0
2 years ago
HELP ASAP ILL GIVE BRAINLIST
SSSSS [86.1K]

Answer:

0.36

Step-by-step explanation:

To find the probability, just multiply.

probability of red candy * probability of pink cookie

0.9*0.4=0.36

I hope this helps!

4 0
2 years ago
The angle of elevation from me to the top of a hill is 51 degrees. The angle of elevation from me to the top of a tree is 57 deg
julia-pushkina [17]

Answer:

Approximately 101\; \rm ft (assuming that the height of the base of the hill is the same as that of the observer.)

Step-by-step explanation:

Refer to the diagram attached.

  • Let \rm O denote the observer.
  • Let \rm A denote the top of the tree.
  • Let \rm R denote the base of the tree.
  • Let \rm B denote the point where line \rm AR (a vertical line) and the horizontal line going through \rm O meets. \angle \rm B\hat{A}R = 90^\circ.

Angles:

  • Angle of elevation of the base of the tree as it appears to the observer: \angle \rm B\hat{O}R = 51^\circ.
  • Angle of elevation of the top of the tree as it appears to the observer: \angle \rm B\hat{O}A = 57^\circ.

Let the length of segment \rm BR (vertical distance between the base of the tree and the base of the hill) be x\; \rm ft.

The question is asking for the length of segment \rm AB. Notice that the length of this segment is \mathrm{AB} = (x + 20)\; \rm ft.

The length of segment \rm OB could be represented in two ways:

  • In right triangle \rm \triangle OBR as the side adjacent to \angle \rm B\hat{O}R = 51^\circ.
  • In right triangle \rm \triangle OBA as the side adjacent to \angle \rm B\hat{O}A = 57^\circ.

For example, in right triangle \rm \triangle OBR, the length of the side opposite to \angle \rm B\hat{O}R = 51^\circ is segment \rm BR. The length of that segment is x\; \rm ft.

\begin{aligned}\tan{\left(\angle\mathrm{B\hat{O}R}\right)} = \frac{\,\rm {BR}\,}{\,\rm {OB}\,} \; \genfrac{}{}{0em}{}{\leftarrow \text{opposite}}{\leftarrow \text{adjacent}}\end{aligned}.

Rearrange to find an expression for the length of \rm OB (in \rm ft) in terms of x:

\begin{aligned}\mathrm{OB} &= \frac{\mathrm{BR}}{\tan{\left(\angle\mathrm{B\hat{O}R}\right)}} \\ &= \frac{x}{\tan\left(51^\circ\right)}\approx 0.810\, x\end{aligned}.

Similarly, in right triangle \rm \triangle OBA:

\begin{aligned}\mathrm{OB} &= \frac{\mathrm{AB}}{\tan{\left(\angle\mathrm{B\hat{O}A}\right)}} \\ &= \frac{x + 20}{\tan\left(57^\circ\right)}\approx 0.649\, (x + 20)\end{aligned}.

Equate the right-hand side of these two equations:

0.810\, x \approx 0.649\, (x + 20).

Solve for x:

x \approx 81\; \rm ft.

Hence, the height of the top of this tree relative to the base of the hill would be (x + 20)\; {\rm ft}\approx 101\; \rm ft.

6 0
3 years ago
*PLS HELP!!* {The Picture Is In The Attachment}​
ivann1987 [24]

Answer:

Step-by-step explanation:

Supplementary angles add up to 180

∠1 + 50 = 180

∠1 = 180 - 50

∠1 = 130

∠3 +50 = 180   {Supplementary}

∠3 = 180 - 50

∠3 =130

⇒∠1 = ∠3 = 130

3 0
2 years ago
Read 2 more answers
What is the approximate diameter of a sphere with a volume of 268cm3
kogti [31]

Answer:

diameter ≈15.6

Step-by-step explanation:

To solve this;

volume of a sphere = 4/3 πr³

From the question given;

volume of the sphere = 268    

lets substitute   and solve for r

volume of sphere = 4/3 πr³

268 = 4/3 × 3.14 × r³

268 =4.19 × r³

Divide both-side of the equation by 4.19

268/4.19 = r³

63.96 = r³

Take the cube root of both-side

∛63.96 = r

7.8 ≈ r

but diameter = 2r = 2×7.8 =15.6

8 0
3 years ago
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