In 2 + In 8 - In 4 In 4 In 6 In 64 DONE

Mathematics

1 answer:

Alex3 years ago

7 0

Answer:

ln 4

Step-by-step explanation:

plus(+) will become times and minus(-)will become divide. Combine all together as all are in terms of ln

ln (2x8)/4

=ln 4

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Which expression is equivalent to...? Screenshots attached. Please help! Thank you.

Studentka2010 [4]

Answer:

$4x^{3} y^{2} (\sqrt[3]{4 x y})$

Step-by-step explanation:

Another complex expression, let's simplify it step by step...

We'll start by re-writing 256 as 4^4

$\sqrt[3]{256 x^{10} y^{7} } = \sqrt[3]{4^{4} x^{10} y^{7} }$

Then we'll extract the 4 from the cubic root. We will then subtract 3 from the exponent (4) to get to a simple 4 inside, and a 4 outside.

$\sqrt[3]{4^{4} x^{10} y^{7} } = 4 \sqrt[3]{4 x^{10} y^{7} }$

Now, we have x^10, so if we divide the exponent by the root factor, we get 10/3 = 3 1/3, which means we will extract x^9 that will become x^3 outside and x will remain inside.

$4 \sqrt[3]{4 x^{10} y^{7} } = 4x^{3} \sqrt[3]{4 x y^{7} }$

For the y's we have y^7 inside the cubic root, that means the true exponent is y^(7/3)... so we can extract y^2 and 1 y will remain inside.

$4x^{3} \sqrt[3]{4 x y^{7} } = 4x^{3} y^{2} \sqrt[3]{4 x y}$

The answer is then:

$4x^{3} y^{2} \sqrt[3]{4 x y} = 4x^{3} y^{2} (\sqrt[3]{4 x y})$

4 0

3 years ago

Write an equation in slope-intercept form of the line that bisects the angle formed by BA and BC

slega [8]

Given:

Angled formed by ray BA and ray BC is 90 degrees.

To find:

The equation of line that bisects the angle formed by ray BA and ray BC.

Solution:

If a line bisects the angle formed by ray BA and ray BC, then it must be passes through point B and makes angles of 45 degrees with ray BA and ray BC.

It is possible if the line passes though point B(-1,3) and other point (-2,4).

Equation of line is

$y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)$