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never [62]
3 years ago
10

francos dad is three times his age. in 10 years, francos dad will be twice francos age plus 2. How old are franco and his dad no

w?
Mathematics
2 answers:
densk [106]3 years ago
8 0
If we assume the age of Francos is x, then dad will be 3x
In 10 years
Francos = x+10
Dad    = 3x+10
Therefore, 3x+10 =2(x+10)+2
                  3x +10 = 2x+20+2
                           x = 22-10
                            x =12 
Therefore, the present ages will be
Francos = 12 years
 Dad      = 36 years
konstantin123 [22]3 years ago
5 0
Let

Y
 be the age of Franco's dad.
X  Franco's age

Y = 3*X                           (1)
(Y +10) = 2*(X+10) +2            (2
)


(3*X  +10) = 2*X +20 +2   

(3-2)X = 22 -10

X = 12 years old  (Franco)

Y = 3*12 = 36 years old (Franco's dad)


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Answer:

v(-3)=23\\v(0)=14\\v(4)=2

Step-by-step explanation:

v(x)=14-3x

v(-3)=14-3(-3)\\\\v(-3)=14-(-9)\\\\v(-3)=23

v(0)=14-3(0)\\\\v(0)=14-0\\\\v(0)=14

v(4)=14-3(4)\\\\v(4)=14-12\\\\v(4)=2

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At a 20th high school reunion, all the classmates were asked the number of children they had. The probability of having a partic
finlep [7]

Answer:

a) We need to check two conditions:

1) \sum_{i=1}^n P_i = 1

0.05+0.14+0.34+0.24+0.11+0.07+0.02+0.02+0.01= 1

2) P_i \geq 0 , \forall i=1,2,...,n

So we satisfy the two conditions so then we have a probability distribution

b) P(C \geq 1)

And we can use the complement rule and we got:

P(C \geq 1)= 1-P(C

c) P(C=0) = 0.05

d) For this case we see that the result from part b use the probability calculated from part c using the complement rule.

Step-by-step explanation:

For this case we have the following probability distribution given:

C    0        1        2         3       4       5        6       7        8      

P  0.05   0.14   0.34   0.24  0.11  0.07  0.02  0.02  0.01

And we assume the following questions:

a) Verify that this is a probability distribution

We need to check two conditions:

1) \sum_{i=1}^n P_i = 1

0.05+0.14+0.34+0.24+0.11+0.07+0.02+0.02+0.01= 1

2) P_i \geq 0 , \forall i=1,2,...,n

So we satisfy the two conditions so then we have a probability distribution

b) What is the probability one randonmly chosen classmate has at least one child

For this case we want this probability:

P(C \geq 1)

And we can use the complement rule and we got:

P(C \geq 1)= 1-P(C

c) What is the probability one randonmly chosen classmate has no children

For this case we want this probability:

P(C=0) = 0.05

d) Look at the answers for parts b and c and explain their relationship

For this case we see that the result from part b use the probability calculated from part c using the complement rule.

5 0
3 years ago
HELP ME PLEASE I BEG YOU
spayn [35]

Answer:

∠ K = 35° and ∠ L = 105°

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

let ∠ K = x then ∠ L = 3x

Sum the angles and equate to 180

3x + x + 40 = 180, that is

4x + 40 = 180 ( subtract 40 from both sides )

4x = 140 ( divide both sides by 4 )

x = 35

Thus

∠ K = 35° and ∠ K = 3x = 3 × 35 = 105°

5 0
3 years ago
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