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never [62]
3 years ago
10

francos dad is three times his age. in 10 years, francos dad will be twice francos age plus 2. How old are franco and his dad no

w?
Mathematics
2 answers:
densk [106]3 years ago
8 0
If we assume the age of Francos is x, then dad will be 3x
In 10 years
Francos = x+10
Dad    = 3x+10
Therefore, 3x+10 =2(x+10)+2
                  3x +10 = 2x+20+2
                           x = 22-10
                            x =12 
Therefore, the present ages will be
Francos = 12 years
 Dad      = 36 years
konstantin123 [22]3 years ago
5 0
Let

Y
 be the age of Franco's dad.
X  Franco's age

Y = 3*X                           (1)
(Y +10) = 2*(X+10) +2            (2
)


(3*X  +10) = 2*X +20 +2   

(3-2)X = 22 -10

X = 12 years old  (Franco)

Y = 3*12 = 36 years old (Franco's dad)


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4 years ago
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ryzh [129]

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3 years ago
(2/3 - 3/4 × 1/8) ÷ (2/3 - 3/4 + 5/8)
kati45 [8]
<h3>Given:</h3>

( \frac{2}{3}  -  \frac{3}{4}  \times  \frac{1}{8} ) \div ( \frac{2}{3}  -  \frac{3}{4}  +  \frac{5}{8} )

<h3>Solution:</h3>

First, solve the brackets.

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( \frac{2}{3}  -  \frac{3}{4}  \times  \frac{1}{8} )

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( \frac{2}{3}   - \frac{3}{4}  +  \frac{5}{8} )

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3 0
2 years ago
Read 2 more answers
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Ganezh [65]

Answer:

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Step-by-step explanation:

Consider the provided information.

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f(x)\left\{\begin{matrix} \frac{1}{0.030}& -0.015

The probability that such errors will be between –0.002 and 0.003 is:

P(-0.002\leq x\leq 0.003)=\int\limits^{0.003}_{-0.002} {\frac{1}{0.030}} \, dx

P(-0.002\leq x\leq 0.003)=\frac{1}{0.030}[x]^{0.003}_{-0.002}

P(-0.002\leq x\leq 0.003)=\frac{0.003+0.002}{0.030}=0.1667

Hence, the required probability is 0.1667

4 0
3 years ago
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balu736 [363]

Answer:

The original number is 83.1

Step-by-step explanation:

Let

x -----> the original number

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3 0
3 years ago
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