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sp2606 [1]
3 years ago
9

Can Someone plz help me with the question??

Mathematics
2 answers:
Anestetic [448]3 years ago
7 0

Answer:

\boxed{x^2+y^2 = 49}

Step-by-step explanation:

First, we'll find the length of the radius using distance formula and the coordinates (0,0) and (7,0)

Distance Formula = \sqrt{(x2-x1)^2+(y2-y1)^2}

R = \sqrt{(7-0)^2+(0-0)^2}

R = \sqrt{7^2}

Radius = 7 units

<u><em>Now, Equation of circle:</em></u>

(x-a)^2+(y-b)^2 = R^2

Where (a,b) = (0,0) So, a = 0, b = 0 and R = 7 units

=> (x-0)^2+(y-0)^2 = (7)^2

=> x^2+y^2 = 49

This is the required equation of the circle.

Alika [10]3 years ago
4 0

Answer:

x^2 + y^2 = 49

Step-by-step explanation:

We can write the equation of a circle as

( x-h) ^2 + ( y-k) ^2 = r^2

where ( h,k) is the center and r is the radius

The radius is the distance from the center to a point on the circle

(0,0) to (7,0) is 7 units

so the the radius is 7

( x-0) ^2 + ( y-0) ^2 = 7^2

x^2 + y^2 = 49

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vaieri [72.5K]

Answer:

\lim\limits_{(x,y)\rightarrow(0,0)}\left(\sqrt{-2x^2-6y^2+1}+1\right)=2

Step-by-step explanation:

We need to first simplify the expression using rationalization(i.e. if a square root term exists in the denominator, then multiply and divide the whole expression by the denominator(but the change the sign of its middle term))

here, we need to find:

\lim\limits_{(x,y)\rightarrow(0,0)}\left(\dfrac{-2x^2-6y^2}{\sqrt{-2x^2-6y^2+1}-1}\right)

first we'll rationalize our expression:

\dfrac{-2x^2-6y^2}{\sqrt{-2x^2-6y^2+1}-1}\left(\dfrac{\sqrt{-2x^2-6y^2+1}+1}{\sqrt{-2x^2-6y^2+1}+1}\right)

\dfrac{-(2x^2+6y^2)(\sqrt{-2x^2-6y^2+1}+1)}{(\sqrt{-2x^2-6y^2+1}+1)^2-(1)^2}

\dfrac{-(2x^2+6y^2)(\sqrt{-2x^2-6y^2+1}+1)}{-2x^2-6y^2+1-1}

\dfrac{-(2x^2+6y^2)(\sqrt{-2x^2-6y^2+1}+1)}{-(2x^2+6y^2)}

\sqrt{-2x^2-6y^2+1}+1

this is our simplified expression, now we can apply our limits:

\lim\limits_{(x,y)\rightarrow(0,0)}\left(\sqrt{-2x^2-6y^2+1}+1\right)

\sqrt{-2(0)^2-6(0)^2+1}+1

1+1

2

the limit does exists and it is 2.

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3 years ago
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Answer:

B. Who is the principal

Step-by-step explanation:

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For question 1 you can try dividing each of the value

For instance, you can divide 9 by 25 and see if you get a nice number

e.g. 1/8=0.125, numbers like these

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e.g 0.650, you would be plotting 650/1000 and you would simplify the fraction to the lowest value any value above the decimal point you can multiply by the denominator and add the nominator value to get your final answer.

Step-by-step explanation:

5 0
3 years ago
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