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sp2606 [1]
3 years ago
9

Can Someone plz help me with the question??

Mathematics
2 answers:
Anestetic [448]3 years ago
7 0

Answer:

\boxed{x^2+y^2 = 49}

Step-by-step explanation:

First, we'll find the length of the radius using distance formula and the coordinates (0,0) and (7,0)

Distance Formula = \sqrt{(x2-x1)^2+(y2-y1)^2}

R = \sqrt{(7-0)^2+(0-0)^2}

R = \sqrt{7^2}

Radius = 7 units

<u><em>Now, Equation of circle:</em></u>

(x-a)^2+(y-b)^2 = R^2

Where (a,b) = (0,0) So, a = 0, b = 0 and R = 7 units

=> (x-0)^2+(y-0)^2 = (7)^2

=> x^2+y^2 = 49

This is the required equation of the circle.

Alika [10]3 years ago
4 0

Answer:

x^2 + y^2 = 49

Step-by-step explanation:

We can write the equation of a circle as

( x-h) ^2 + ( y-k) ^2 = r^2

where ( h,k) is the center and r is the radius

The radius is the distance from the center to a point on the circle

(0,0) to (7,0) is 7 units

so the the radius is 7

( x-0) ^2 + ( y-0) ^2 = 7^2

x^2 + y^2 = 49

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\rightarrow z^4=-625\\\\\rightarrow z=(-625+0i)^{\frac{1}{4}}\\\\\rightarrow x+iy=(-625+0i)^{\frac{1}{4}}\\\\ x=r \cos A\\\\y=r \sin A\\\\r \cos A=-625\\\\ r \sin A=0\\\\x^2+y^2=625^{2}\\\\r^2=625^{2}\\\\|r|=625\\\\ \tan A=\frac{0}{-625}\\\\ \tan A=0\\\\ A=\pi\\\\\rightarrow z= [625(\cos (2k \pi+pi) +i \sin (2k\pi+ \pi)]^{\frac{1}{4}}\\\\k=0,1,2,3,4,....\\\\\rightarrow z=(625)^{\frac{1}{4}}[\cos \frac{(2k \pi+pi)}{4} +i \sin \frac{(2k\pi+ \pi)}{4}]

\rightarrow z_{0}=(625)^{\frac{1}{4}}[\cos \frac{pi}{4} +i \sin \frac{\pi)}{4}]\\\\\rightarrow z_{1}=(625)^{\frac{1}{4}}[\cos \frac{3\pi}{4} +i \sin \frac{3\pi}{4}]\\\\ \rightarrow z_{2}=(625)^{\frac{1}{4}}[\cos \frac{5\pi}{4} +i \sin \frac{5\pi}{4}]\\\\ \rightarrow z_{3}=(625)^{\frac{1}{4}}[\cos \frac{7\pi}{4} +i \sin \frac{7\pi}{4}]

Argument of Complex number

Z=x+iy , is given by

If, x>0, y>0, Angle lies in first Quadrant.

If, x<0, y>0, Angle lies in Second Quadrant.

If, x<0, y<0, Angle lies in third Quadrant.

If, x>0, y<0, Angle lies in fourth Quadrant.

We have to find those roots among four roots whose argument is between 270° and 360°.So, that root is

   \rightarrow z_{2}=(625)^{\frac{1}{4}}[\cos \frac{5\pi}{4} +i \sin \frac{5\pi}{4}]

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