Can anyone help me out please

A student's pay of $18 an hour is $4 more than twice the amount the student earns per hour at an internship. Enter and solve an

Natasha2012 [34]

1. You have that a student's pay of $18 an hour is $4 more than twice the amount the student earns per hour at an internship.

2. So, let's call the hourly pay of the internship: "x". Then, you have:

18=2x+4

3. When you clear the variable "x", you obtain:

18-4=2x
14=2x
x=14/2
x=$7

Therefore, the answer is: The hourly pay of the internship is $7.

4 0

3 years ago

Evaluate the radical. 3√27 Enter the answer in the box.

igor_vitrenko [27]

The answer is 3

Hope this Helped :T

3 0

3 years ago

Naval intelligence reports that 99 enemy vessels in a fleet of 1818 are carrying nuclear weapons. If 99 vessels are randomly tar

oee [108]

Answer:

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

Step-by-step explanation:

The vessels are destroyed and then not replaced, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Fleet of 18 means that $N = 18$

9 are carrying nuclear weapons, which means that $k = 9$

9 are destroyed, which means that $n = 9$

What is the probability that no more than 1 vessel transporting nuclear weapons was destroyed?

This is:

$P(X \leq 1) = P(X = 0) + P(X = 1)$

In which

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,18,9,9) = \frac{C_{9,0}*C_{9,9}}{C_{18,9}} = 0.000021$

$P(X = 1) = h(1,18,9,9) = \frac{C_{9,1}*C_{9,8}}{C_{18,9}} = 0.001666$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.000021 + 0.001666 = 0.001687$

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

4 0

3 years ago

Plzzxzzzzzzzzzzzzzzzzzxxzbxbxbxbx lol

tia_tia [17]

Answer:

15.41

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

In 5 OR MORE SENTENCES, write a short story explaining the graph OR write about the key features of the graph.

rewona [7]

The graph illustrated is divided into three seperate sections namely A, B and C, the short story culled from the graph is described thus:

Rate of change or slope = (Rise/ Run)

Rise = y2 - y1
Run = x2 - x1

SECTION A:

Slope = (40 - 0) ÷ (20 - 0) = 40/20 = 2

Distance traveled = 50 meters

SECTION B :

This section gives an horizontal line, hence, the slope is 0.

Distance covered = 0 ; as there was no change in the distance over the period of time.

SECTION C:

Slope = (80 - 50) ÷ (70 - 60) = 30/10 = 3

The total distance traveled = 80 - 50 = 30 meters

The total distance and time spent traveling :

Total distance traveled = (50 + 30) = 80 meters

Total time spent = 70 seconds (time at the 80 meter mark)

Hence, the story.

Learn more : brainly.com/question/25309609

6 0

3 years ago