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3 years ago

After a party you have 1/3 apple pie left and 5/6 pumpkin pie left. How much more pumpkin pie than apple pie is left?

Mathematics

1 answer:

motikmotik3 years ago

6 0

There is 1/2 more pumpkin pie than apple pie left.

1/3 x 2 = 2/6

5/6 - 2/6 = 3/6

3/6 / 3 = 1/2

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AD= 5x and DE= 3x- 2

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Read 2 more answers

V=x/t<br> How do I solve for T

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When solving for a variable in an equation, get it separated from the others onto one side typically the left hand side and rest onto the opposite side usually the right hand side.

V = x / t

First, let us get the 't' variable out of denominator position and then it will be easier to work with.

V * t = (x / t) * t

Why did I multiply each side by 't' and not just the "x / t" expression? That is because every operation we do on one side, we must also do on the opposite side.

Okay, now we get the following equation.

V * t = x

We removed the 't' variable from denominator and in fact, it doesn't even exist anymore on the right hand side!

To complete this question, all we have to do is divide each side by 'V' and we are done!

(V * t) / V = x / V

Comes out to:

t = x / V

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3 years ago

When studying radioactive material, a nuclear engineer found that over 365 days,

Gnom [1K]

Answer:

a) The mean number of radioactive atoms that decay per day is 81.485.

b) 0% probability that on a given day, 50 radioactive atoms decayed.

Step-by-step explanation:

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\lambda}*\lambda^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\lambda$ is the mean in the given interval.

a. Find the mean number of radioactive atoms that decayed in a day.

29,742 atoms decayed during 365 days, which means that:

$\lambda = \frac{29742}{365} = 81.485$

The mean number of radioactive atoms that decay per day is 81.485.

b. Find the probability that on a given day, 50 radioactive atoms decayed.

This is P(X = 50). So

$P(X = 50) = \frac{e^{-81.485}*(81.485)^{50}}{(50)!} = 0$

0% probability that on a given day, 50 radioactive atoms decayed.

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