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BlackZzzverrR [31]
3 years ago
12

PLEASE HELP

Mathematics
2 answers:
Otrada [13]3 years ago
5 0
<span>One cm represented 11 in. in the first scale, but now 1 cm represents 12 in. in the second scale.</span>
SIZIF [17.4K]3 years ago
3 0

Answer:

The correct answer is option A,

One cm represented 11 in. in the first scale, but now 1 cm represents 12 in. in the second scale

Step-by-step explanation:

The earlier planned length was 44 in\\

So the scale of the map was

\frac{44}{4} \\= 11\\1 cm = 11 in\\

The second planned length was 48 in\\

So the second scale of the map was

\frac{48}{4} \\= 12\\1 cm = 12 in\\

Thus, option A is correct.

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If a rectangle A has sides are three times the length of those rectangle B, how do the areas of the two rectangles compare?
Radda [10]

Answer:

The area of A is nine times the area of B.

Step-by-step explanation:

4 0
3 years ago
Pretty Pavers company is installing a driveway. Below is a diagram of the driveway they are
prohojiy [21]

Answer:

The most correct option is;

(B) 958.2 ft.²

Step-by-step explanation:

From the question, the dimension of each square = 3 ft.²

Therefore, the length of the sides of the square = √3 ft.

Based on the above dimensions, the dimension of the small semicircle is found by counting the number of square sides ti subtends as follows;

The dimension of the diameter of the small semicircle = 10·√3

Radius of the small semicircle = Diameter/2 = 10·√3/2 = 5·√3

Area of the small semicircle = (π·r²)/2 = (π×(5·√3)²)/2 = 117.81 ft.²

Similarly;

The dimension of the diameter of the large semicircle = 10·√3 + 2 × 6 × √3

∴ The dimension of the diameter of the large semicircle = 22·√3

Radius of the large semicircle = Diameter/2 = 22·√3/2 = 11·√3

Area of the large semicircle = (π·r²)/2 = (π×(11·√3)²)/2 = 570.2 ft.²

Area of rectangle = 11·√3 × 17·√3 = 561

Area, A of large semicircle cutting into the rectangle is found as follows;

A_{(segment \, of \, semicircle)} = \frac{1}{4} \times (\theta - sin\theta) \times r^2

Where:

\theta = 2\times tan^{-1}( \frac{The \, number \, of  \, vertical  \, squrare  \, sides  \ cut  \,  by  \  the  \  large  \,  semicircle}{The \, number \, of  \, horizontal \, squrare  \, sides  \ cut  \,  by  \  the  \  large  \,  semicircle} )

\therefore \theta = 2\times tan^{-1}( \frac{10\cdot \sqrt{3} }{5\cdot \sqrt{3}} ) = 2.214

Hence;

A_{(segment \, of \, semicircle)} = \frac{1}{4} \times (2.214 - sin2.214) \times (11\cdot\sqrt{3} )^2 = 128.3 \, ft^2

Therefore; t

The area covered by the pavers = 561 - 128.3 + 570.2 - 117.81 = 885.19 ft²

Therefor, the most correct option is (B) 958.2 ft.².

4 0
3 years ago
The 1st term in a geometric series is 5 and the common ratio is 2. Find the sum of the 1st 10 terms in the series.
lesya [120]

Answer:

5115

Step-by-step explanation:

a1(1-(r)^n)/1-r

5(1-(2.00)^10)/1-2.00

3 0
3 years ago
3 1/7 + 4 3/14 = ?<br>plz help me ​
ale4655 [162]
Convert the mixed numbers to improper fractions, then find the LCD and combine.
Exact Form:
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7.35714285
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