Question

Alan sells custom made kites online. He makes a flat profit of $20 per kite, but he pays $20 per day for his website. Write an inequality that gives the number of kites Alan needs to sell to make at least $900 per week?

Answer 1

Profit on each kite that Allan sells= $ 20 per kite

Amount paid by Allan for his Website = $ 20 per day

Let number of kites sold by Allan per day = x

In 7 days , number of kites sold = 7 x

Amount paid by Allan for his Website in 7 seven days = 20 × 7=$140

We have to make an equality describing number of kites Alan needs to sell to make at least $900 per week.

The Inequality is

→20×7 x -140 ≥ 900

→ 140 x ≥ 900 + 140

→ 140 x ≥1040

→ 7 x ≥ 52 (Minimum number of kites that allan should sell in a week)

Dividing both sides by 140,we get

→ x ≥ $\frac{1040}{140}=7.43$= 8 kites in a day(approx)

Answer 2

20x+20y=900
I hope that helps. You'll have to isolate each variable. X= kite, y=website.