I think it is <span>C) The origin is included in the shaded region and the shaded area is above the line. </span>
Part (a)
Plug in y = 0 and solve for x. Use the zero product property
y = x(x+3)(x-2)
0 = x(x+3)(x-2)
x(x+3)(x-2) = 0
x = 0 or x+3 = 0 or x-2 = 0 .... zero product property
x = 0 or x = -3 or x = 2
The three roots or zeros are x = 0 or x = -3 or x = 2
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Part (b)
The roots of the graph are: x = -2, x = 1, x = 3. Each root is where the graph crosses or touches the horizontal x axis.
Note how x = 0 is found in part (a), but not found here. This is one example where the graphs don't match. Another would be x = -3 is in part (a), but not here.
So that's why the graph does <u>not</u> match with the function in part (a)
y = -x + 5
5x + 2y = 14
5x + 2(-x + 5) = 14
5x + 2(-x) + 2(5) = 14
5x - 2x + 10 = 14
3x + 10 = 14
- 10 - 10
3x = 4
3 3
x = 1¹/₃
y = -x + 5
y = -1¹/₃ + 5
y = 3²/₃
(x, y) = (-1¹/₂, 3²/₃)
I think the 4th one but Im not too sure please forgive me if I'm wrong.
Answer:
I am sorry but this is too difficult
Step-by-step explanation:
I recommend asking a teacher for help not to be rude
