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Sever21 [200]
3 years ago
14

800 out of 1/10 is what?

Mathematics
2 answers:
dexar [7]3 years ago
5 0

The answer is 80.

Please mark brainliest

lesya692 [45]3 years ago
4 0

Answer:

If you meant what is 1/10 of 80 the answer is 80

Step-by-step explanation:

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A bad contains two red marbles, six blue marbles and seven green marbles. If two marbles are drawn out of the bag, what is the p
Luba_88 [7]

Answer:

1/105

Step-by-step explanation:

Total Marbles= 2+6+7=15

2/15 * 1/14 = 2/210 = 1/105

(It becomes 1/14 since you take out own red marble)

8 0
2 years ago
10 You work at a factory that bottles honey The factory bottles S250 gallons of honey into cup size bottles on average a ay How
erma4kov [3.2K]

Answer:

The factory bottles <u>4000 cups of hone</u>y a day.

Step-by-step explanation:

1 gallon = 16 cups

250 gallons = 4000 cups

Hope this helps!

8 0
4 years ago
The table below shows the squares of different numbers:
pentagon [3]
Part A:

Yes this is a function of x. Specifically the function is f(x) = x^2
The inputs (x) are squared to get the outputs (y). 
For example,
f(x) = x^2
f(-3) = (-3)^2 <<--- input is x = -3
f(-3) = 9 <<--- output is 9
The pair of values -3 and 9 are shown in the table (column on the very right side)

The fact that each input leads to exactly one output is what makes this a function. If we had an input lead to multiple outputs, then it wouldn't be a function.

=============================================================

Part B

Replace every x with 150 and then use the order of operations PEMDAS to simplify

f(x) = 20+3x
f(x) = 20+3*x
f(150) = 20+3*150 <<--- x has been replaced with 150
f(150) = 20+300
f(150) = 320
So the value of f(150) is 320
The input is 20
The output is 320
x is the number of hours
y or f(x) is the total cost

So this means f(150) = 320 represents the idea that 150 hours of renting the rowboat leads to a total cost of $320

6 0
4 years ago
"If two lines intersect, then the intersection is a point." What is the hypothesis? Two lines intersect
larisa86 [58]

Answer:

Hypothesis is: Intersection happens at a point

Step-by-step explanation:

A hypothesis in science is a suggested explanation of something that has a consequence or leads to an occurrence.  Usually it will be written in the form of an "if and then" statement.

Such statement explains what would occur, or follow if the possibility enunciated in the "if" part of the statement happens.

In this case the hypothesis is that if there is intersection of lines, it has to occur at a point. Therefore the closest to that statement among the options given in the problem is the last one: "Intersection happens at a point"

5 0
3 years ago
At an interest rate of 8% compounded annually, how long will it take to double the following investments?
Paladinen [302]
Let's see, if the first one has a Principal of $50, when it doubles the accumulated amount will then be $100,

recall your logarithm rules for an exponential,

\bf \textit{Logarithm of exponentials}\\\\&#10;log_{{  a}}\left( x^{{  b}} \right)\implies {{  b}}\cdot  log_{{  a}}(x)\\\\&#10;-------------------------------\\\\&#10;\qquad \textit{Compound Interest Earned Amount}&#10;\\\\&#10;

\bf A=P\left(1+\frac{r}{n}\right)^{nt}&#10;\quad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\to &\$100\\&#10;P=\textit{original amount deposited}\to &\$50\\&#10;r=rate\to 8\%\to \frac{8}{100}\to &0.08\\&#10;n=&#10;\begin{array}{llll}&#10;\textit{times it compounds per year}\\&#10;\textit{annnually, thus once}&#10;\end{array}\to &1\\&#10;t=years&#10;\end{cases}&#10;\\\\\\&#10;100=50\left(1+\frac{0.08}{1}\right)^{1\cdot t}\implies 100=50(1.08)^t&#10;\\\\\\&#10;\cfrac{100}{50}=1.08^t\implies 2=1.08^t\implies log(2)=log(1.08^t)&#10;\\\\\\&#10;

\bf log(2)=t\cdot log(1.08)\implies \cfrac{log(2)}{log(1.08)}=t\implies 9.0065\approx t\\\\&#10;-------------------------------\\\\&#10;

now, for the second amount, if the Principal is 500, the accumulated amount is 1000 when doubled,

\bf \qquad \textit{Compound Interest Earned Amount}&#10;\\\\&#10;A=P\left(1+\frac{r}{n}\right)^{nt}&#10;\quad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\to &\$1000\\&#10;P=\textit{original amount deposited}\to &\$500\\&#10;r=rate\to 8\%\to \frac{8}{100}\to &0.08\\&#10;n=&#10;\begin{array}{llll}&#10;\textit{times it compounds per year}\\&#10;\textit{annnually, thus once}&#10;\end{array}\to &1\\&#10;t=years&#10;\end{cases}&#10;\\\\\\&#10;1000=500\left(1+\frac{0.08}{1}\right)^{1\cdot t}\implies 1000=500(1.08)^t&#10;\\\\\\&#10;

\bf \cfrac{1000}{500}=1.08^t\implies 2=1.08^t\implies log(2)=log(1.08^t)&#10;\\\\\\&#10;log(2)=t\cdot log(1.08)\implies \cfrac{log(2)}{log(1.08)}=t\implies 9.0065\approx t\\\\&#10;-------------------------------

now, for the last, Principal is 1700, amount is then 3400,

\bf \qquad \textit{Compound Interest Earned Amount}&#10;\\\\&#10;A=P\left(1+\frac{r}{n}\right)^{nt}&#10;\quad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\to &\$3400\\&#10;P=\textit{original amount deposited}\to &\$1700\\&#10;r=rate\to 8\%\to \frac{8}{100}\to &0.08\\&#10;n=&#10;\begin{array}{llll}&#10;\textit{times it compounds per year}\\&#10;\textit{annnually, thus once}&#10;\end{array}\to &1\\&#10;t=years&#10;\end{cases}

\bf 3400=1700\left(1+\frac{0.08}{1}\right)^{1\cdot t}\implies 3400=1700(1.08)^t&#10;\\\\\\&#10;\cfrac{3400}{1700}=1.08^t\implies 2=1.08^t\implies log(2)=log(1.08^t)&#10;\\\\\\&#10;log(2)=t\cdot log(1.08)\implies \cfrac{log(2)}{log(1.08)}=t\implies 9.0065\approx t
8 0
4 years ago
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