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MrRa [10]
1 year ago
10

1, 1, 5, 5, 7, 8, 8, 10, 12

Mathematics
1 answer:
stepan [7]1 year ago
4 0

Answer:

ррооо

Step-by-step explanation:

Нажмите на фрагмент, чтобы вставить его в текстовое поле.

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Its not math but I still need helppppp​
Angelina_Jolie [31]

Answer:

T

Step-by-step explanation:

4 0
3 years ago
a class has six boys and 14 girls what is the ratio in simplest form that compares number of boys the number of students​
-BARSIC- [3]

Answer:

3:10

Step-by-step explanation:

Boys- 6

Girls- 14

Total students- 20

Boys:Total students

   6   :      20

Simplify:

6/2=3

20/2=10

This is written as:

3:10

➴Hope this helps!

➸CloutAnswers

6 0
3 years ago
8v-3v-3+7v simplified
Licemer1 [7]

Your answer is <u>12v-3.</u>

-

Steps:

1. Group Like Terms. (8v-3v+7v-3)

2. Add Similar Elements. (8v-3v+7v=12v)

3. Finished. (=12v-3)

-

Hope this helped :)

3 0
2 years ago
Use synthetic division to divide (x^ 3 + x^ 2 – 40x – 4) ÷ (x – 6)
Marina CMI [18]
The answer is C.

Hope this helps!!

7 0
2 years ago
Read 2 more answers
You coach a basketball ball team of 12 players; 5 players must be on the floor at all times; Figuring that every player can play
makvit [3.9K]
The function "choose k from n", nCk, is defined as
  nCk = n!/(k!*(n-k)!) . . . . . where "!" indicates the factorial

a) No position sensitivity.
The number of possibilities is the number of ways you can choose 5 players from a roster of 12.
  12C5 = 12*11*10*9*8/(5*4*3*2*1) = 792
You can put 792 different teams on the floor.

b) 1 of 2 centers, 2 of 5 guards, 2 of 5 forwards.
The number of possibilities is the product of the number of ways, for each position, you can choose the required number of players from those capable of playing the position.
  (2C1)*(5C2)*(5C2) = 2*10*10 = 200
You can put 200 different teams on the floor.
4 0
3 years ago
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