Asymptote at x = 3 and a horizontal asymptote at y = 1. The curves approach these asymptotes but never cross them. The method used to find the horizontal asymptote changes depending on how the degrees of the polynomials in the numerator and denominator of the function compare.
Answer:
8x+y-13=0
Step-by-step explanation:
let the given point be
A(1,5)=(x1,y1)
slope(m)= -8
then,equation of straight line is,
(y-y1)=m(x-x1)
(y-5)= -8(x-1)
y-5= -8x+8
8x+y-5-8=0
therefore,8x+y-13=0 ..........(i) is the required equation.
Answer:
Its 40.9!
Step-by-step explanation:
The opposite sides of angles are most of the time congruent, or the same!
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