In a race, the second place finisher crossed the finish line 1 1/3 minutes after the winner. the third place finisher was 1 3/ m
1 answer:
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The required value of mean and variance is 203 and 3942 respectively.
Hence option B is correct.
The sample includes the following claims: 192, 113, 200, 287, and 225.
<h3>What is Statistic?</h3>The statistic is the study of mathematics which deal with relations between comprehensive data.
Mean(x) = 192+113+200+287+225/5
x = 203
variance =
=summation of squared value/n^2−1
=15769/25−1
=15769/24
=3942
Thus, the required value of mean and variance is 203 and 3942 respectively.
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So : 
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First, you want to bring everything together on the top of the fraction.
12=24/2 so you can have
Add like terms -- 12 +24 = 36
Now we are at
Which is the lowest possible simplified version while remaining at exact value.
Feel free to check my math! I kinda did this off the top of my head.
First, you want to bring everything together on the top of the fraction.
12=24/2 so you can have
Add like terms -- 12 +24 = 36
Now we are at
Feel free to check my math! I kinda did this off the top of my head.
