Answer:
0 boxes minimum
Step-by-step explanation:
The mass of the truck and paper must satisfy ...
22.5b + 2948.35 ≤ 4700 . . . . total truck mass cannot exceed bridge limits
22.5b ≤ 1751.65
b ≤ 77.85
The driver can take a minimum of 0 boxes and a maximum of 77 boxes of paper over the bridge.
_____
The question asks for the <em>minimum</em>. We usually expect such a question to ask for the <em>maximum</em>.
2 42/100 turn it to a fraction
Required number = 1/2 (2/7 + 3/4)
= 1/2 ((8 + 21)/28)
= {1/2 × 29/28)
= 29/56
Hence, 29/56 is a rational number lying halfway between 2/7 and 3/4.
