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BARSIC [14]
2 years ago
14

1.1 solve for x, where 0°< x 90°. write your answer to one decimal place. 1.1.1 tanx=sin38° 1.1.2cosec( x+10°)=1.345​

Mathematics
1 answer:
snow_lady [41]2 years ago
5 0

The value of x in tan(x)=sin38° is 31.6 and the value of x in cosec(x+10°)=1.345​ is 38.0

<h3>How to solve the trigonometry ratios?</h3>

The equations are given as:

tan(x)=sin38°

cosec( x+10°)=1.345​

In tan(x)=sin38°, we have:

tan(x)=0.6157

Take the arc tan of both sides

x = 31.6

Also, we have:

cosec(x+10°)=1.345​

Take the inverse of both sides

sin(x+10°) = 0.7434

Take the arc sin of both sides

x+10 = 48.0

Subtract 10 from both sides

x = 38.0

Hence, the value of x in tan(x)=sin38° is 31.6 and the value of x in cosec(x+10°)=1.345​ is 38.0

Read more about trigonometry ratios at:

brainly.com/question/11967894

#SPJ1

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8 0
3 years ago
(I) x²-8x = -16<br>(ii) x²+2x+1 = 0<br>(iii) 4x²-24x-36=0<br>Solve please...........​
algol13

(I)

Given equation is x²-8x = -16

⇛ x²-8x+16 = 0

⇛ x²-4x-4x+16 = 0

⇛ x(x-4)-4(x-4) = 0

⇛ (x-4)(x-4) = 0

⇛ x-4 = 0 or x-4 = 0

⇛ x = 4 or x = 4

(ii)

Given equation is x²+2x+1 = 0

⇛ x²+x+x+1 = 0

⇛ x(x+1)+1(x+1) = 0

⇛ (x+1)(x+1) = 0

⇛ x+1 = 0 or x+1 = 0

⇛ x = -1 or x = -1

(iii)

Given equation is 4x²-24x-36 = 0

⇛ 4(x²-6x-9) = 0

⇛ x²-6x-9 = 0

⇛ x²-2(x)(3) = 9

On adding 3² both sides then

⇛ x²-2(3)x)+3² = 9+9

⇛ (x-3)² = 18

⇛ (x-3) = ±√18

⇛ x-3 = ±√(2×9)

⇛ x-3 = ±3√2

⇛ x = 3±3√2

⇛ x = 3+3√2 or 3-3√2

5 0
2 years ago
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