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zlopas [31]
4 years ago
5

How do I solve this problem?

Mathematics
1 answer:
cluponka [151]4 years ago
5 0
\text {Area of a triangle = }  \dfrac{1}{2} \times \text{base} \times \text{height}

\text {Area of a triangle = }

\dfrac{1}{2} \times  \dfrac{2x^2 - x - 1}{x-3} \times  \dfrac{2x^2 +2x - 24}{2x + 1}

= \dfrac{1}{2} \times  \dfrac{(x-1)(2x+1)}{x-3} \times  \dfrac{2(x+4)(x-3)}{2x + 1}

= (x -1 )(x +4)

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