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pentagon [3]
3 years ago
12

Help plz (filling in 20 characters)

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
5 0
4. as a decimal = 1.8 then to a percent = 180%
5. it's already a decimal so it = 0.15%
6. also already a decimal so it = 275%

to get from a decimal to a percent, move the decimal 2 spaces to the right and add a percent symbol at the end
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-3*e^(5w)=-88 Solve the equation for w. Express the solution as a logarithm in base-e.
Lilit [14]

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Michael had $550 in his savings account. He took out $30.75 every month for one year. What is the net change in Michael's accoun
kozerog [31]
$30.75 x 12 = 369
$550-$369 =$181
7 0
3 years ago
What is 3,493 divided by 37? Please include it’s remainder, too;
qwelly [4]

94 remainder 4054054

7 0
3 years ago
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1) Use power series to find the series solution to the differential equation y'+2y = 0 PLEASE SHOW ALL YOUR WORK, OR RISK LOSING
iogann1982 [59]

If

y=\displaystyle\sum_{n=0}^\infty a_nx^n

then

y'=\displaystyle\sum_{n=1}^\infty na_nx^{n-1}=\sum_{n=0}^\infty(n+1)a_{n+1}x^n

The ODE in terms of these series is

\displaystyle\sum_{n=0}^\infty(n+1)a_{n+1}x^n+2\sum_{n=0}^\infty a_nx^n=0

\displaystyle\sum_{n=0}^\infty\bigg(a_{n+1}+2a_n\bigg)x^n=0

\implies\begin{cases}a_0=y(0)\\(n+1)a_{n+1}=-2a_n&\text{for }n\ge0\end{cases}

We can solve the recurrence exactly by substitution:

a_{n+1}=-\dfrac2{n+1}a_n=\dfrac{2^2}{(n+1)n}a_{n-1}=-\dfrac{2^3}{(n+1)n(n-1)}a_{n-2}=\cdots=\dfrac{(-2)^{n+1}}{(n+1)!}a_0

\implies a_n=\dfrac{(-2)^n}{n!}a_0

So the ODE has solution

y(x)=\displaystyle a_0\sum_{n=0}^\infty\frac{(-2x)^n}{n!}

which you may recognize as the power series of the exponential function. Then

\boxed{y(x)=a_0e^{-2x}}

7 0
3 years ago
Find x. (Finding an angle measure given extended triangles) Please help
Alja [10]
50+79=129
180-129=51
X=51

Explanations
Angles on a straight line add up to 180 degrees. So 180-101=79 degrees
50 degrees is an opposite angle so it moves into the internal angle.
Angles in a triangle add up to 180 so (180-50-79=51)
Ans is 51 I think
8 0
3 years ago
Read 2 more answers
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