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Svetradugi [14.3K]
3 years ago
11

Prove that parallelogram circumscribing a circle is a rhombus​

Mathematics
1 answer:
Romashka [77]3 years ago
6 0

Answer:

Answer:

Step-by-step explanation:

I hope it's helpful!

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Read 2 more answers
Suppose the ages of multiple birth mothers (4 or more births) are normally distributed with a mean age of 35.5 years and a stand
Ann [662]

Answer:

40.65% of these mothers are between the ages of 32 to 40

23.27% of these mothers are less than 30 years old

37.07% of these mothers are more than 38 years old

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 35.5, \sigma = 7.5

What percent of these mothers are between the ages of 32 to 40?

This is the pvalue of Z when X = 40 subtracted by the pvalue of Z when X = 32.

X = 40

Z = \frac{X - \mu}{\sigma}

Z = \frac{40 - 35.5}{7.5}

Z = 0.6

Z = 0.6 has a pvalue of 0.7257

X = 32

Z = \frac{X - \mu}{\sigma}

Z = \frac{32 - 35.5}{7.5}

Z = -0.47

Z = -0.47 has a pvalue of 0.3192

0.7257 - 0.3192 = 0.4065

40.65% of these mothers are between the ages of 32 to 40

What percent of these mothers are less than 30 years old?

This is the pvalue of Z when X = 30.

Z = \frac{X - \mu}{\sigma}

Z = \frac{30 - 35.5}{7.5}

Z = -0.73

Z = -0.73 has a pvalue of 0.2327

23.27% of these mothers are less than 30 years old

What percent of these mothers are more than 38 years old?

This is 1 subtracted by the pvalue of Z when X = 38.

Z = \frac{X - \mu}{\sigma}

Z = \frac{38 - 35.5}{7.5}

Z = 0.33

Z = 0.33 has a pvalue of 0.6293

1 - 0.6293 = 0.3707

37.07% of these mothers are more than 38 years old

5 0
3 years ago
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