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hram777 [196]
3 years ago
9

What is the equation to a graph with the vertex -1,3 and zeros -4 and -2

Mathematics
1 answer:
Mashutka [201]3 years ago
5 0

Answer:

f(x)=x^2+6x+8

Step-by-step explanation:

We are given zeros as x=-4, x=-2

so, we can set up function as

f(x)=a(x+4)(x+2)

Vertex is at (-1,3)

It means that graph passes through point (-1,3)

so, we can plug x=-1 and f(x)=3

and then we can solve for 'a'

3=a(-1+4)(-1+2)

we get

a=1

now, we can plug it back

and we get

f(x)=1(x+4)(x+2)

now, we can simplify it

f(x)=x^2+6x+8

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Put these in order from greatest to least.
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Plzzz HELP will give brainliest 9^-53*9^37
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9^(-53) * 9^(37)

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3 0
3 years ago
Solve this equation for A:A ÷ 2 = 4        A. 2   B. 6   C. 8   D. 4
algol13

Answer:

C) 8

Step-by-step explanation:

A ÷ 2 = 4

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A = 2 * 4

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Annual starting salaries for college graduates with degrees in business administration are generally expected to be between $10,
Andreyy89

Answer:

1) the planning value for the population standard deviation is 10,000

2)

a) Margin of error E = 500, n = 1536.64 ≈ 1537

b) Margin of error E = 200, n = 9604

c) Margin of error E = 100, n = 38416

3)

As we can see, sample size corresponding to margin of error of $100 is too large and may not be feasible.

Hence, I will not recommend trying to obtain the $100 margin of error in the present case.

Step-by-step explanation:

Given the data in the question;

1) Planning Value for the population standard deviation will be;

⇒ ( 50,000 - 10,000 ) / 4

= 40,000 / 4

σ = 10,000

Hence, the planning value for the population standard deviation is 10,000

2) how large a sample should be taken if the desired margin of error is;

we know that, n = [ (z_{\alpha /2 × σ ) / E ]²

given that confidence level = 95%, so z_{\alpha /2  = 1.96

Now,

a) Margin of error E = 500

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 500 ]²

n = [ 19600 / 500 ]²

n = 1536.64 ≈ 1537

b) Margin of error E = 200

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 200 ]²

n = [ 19600 / 200 ]²

n = 9604

c)  Margin of error E = 100

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 100 ]²

n = [ 19600 / 100 ]²

n = 38416

3) Would you recommend trying to obtain the $100 margin of error?

As we can see, sample size corresponding to margin of error of $100 is too large and may not be feasible.

Hence, I will not recommend trying to obtain the $100 margin of error in the present case.

7 0
3 years ago
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