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3 years ago

What is the area and circumference of a circle with the diameter of 72m

Mathematics

1 answer:

serious [3.7K]3 years ago

4 0

Answer:

Area: 4071.5m²

Circumference: 226.19m

plz mark me as brainliest :)

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Jason took his girlfriend to dinner at a nice restaurant. the bill was $84.20 and he needs to give a 15% tip. How much tip shoul

marysya [2.9K]

Answer:

Tip Total: $ 12.63

Tip Each Person: $ 6.32

Total (Bill + Tip): $ 96.83

Total Each Person: $ 48.42

Step-by-step explanation:

3 0

3 years ago

2 Points

masya89 [10]

The answer is 120. Because inscribed angle is Half of the arc measure. Double 60 and we get 120.

6 0

3 years ago

Read 2 more answers

If a = 7 and b = 11, what is the measure of ∠B? (round to the nearest tenth of a degree) A) 32.5° B) 39.2° C) 50.5° D) 57.5°

Ilia_Sergeevich [38]

Answer:

D) 57.5°

Step-by-step explanation:

As the question is not complete. So, let's suppose it is a right angle triangle then, we can apply Pythagoras theorem to calculate the hypotenuse or the third side.

Pythagoras Theorem = $c^{2}$ = $a^{2} + b^{2}$

a = 7 and b = 11

$a^{2}$ = 49

$b^{2}$ = 121

Plugging in the values, we will get:

$c^{2}$ = 49 + 121

$c^{2}$ = 170

c = $\sqrt{170}$

To calculate the unknown angle B, we can use law of sine.

Law of sine = $\frac{a}{sinA}$ = $\frac{b}{sinB}$ = $\frac{c}{sinC}$

So,

$\frac{c}{sinC}$ = $\frac{b}{sinB}$

$\frac{\sqrt{170} }{sin90}$ = $\frac{11}{sinB}$

Sin90 = 1

sinB = $\frac{11}{\sqrt{170} }$

B = $sin^{-1}$ ( $\frac{11}{\sqrt{170} }$ )

B = 57.5°

8 0

3 years ago

Is this statement always, sometimes, or never true.

cestrela7 [59]

Answer:

Never true

Step-by-step explanation:

Linear angles are adjacent angles whose sum is 180

3 0

3 years ago

642 x 115 worked out ?

lys-0071 [83]

Answer:

642x115=73830

Step-by-step explanation:

does that help?

8 0

3 years ago

Read 2 more answers