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liubo4ka [24]
3 years ago
9

What is the range of the function f(x) = |x| – 3?

Mathematics
1 answer:
Likurg_2 [28]3 years ago
3 0
Why not draw the graph of y=|x|?  It has a v-shape, and the vertex is at (0,0).

The graph of f(x) = |x| - 3 looks exactly the same, EXCEPT that the whole graph of |x| is shifted 3 units downward.  The smallest value that y can have is therefore -3.

Can you now figure out the range of f(x)?
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Part 1:
alexira [117]

The size of the corner you need to cut in order for your box to have this area is 0.5 inches

<h3>Part 1: A. Express the new length of the long side of the note card, once the two corners are removed.</h3>

The base length is given as:

Length = 7

When the edges are removed, the new length becomes

New length = 7 - x - x

Evaluate

New length = 7 - 2x

<h3>Part 1: B. Express the new width of the short side of the note card, once the two corners are removed.</h3>

The base width is given as:

Width = 4

When the edges are removed, the new length becomes

New width = 4 - x - x

Evaluate

New width = 4 - 2x

<h3>Part 2: Write a function A(x) that defines the area of the bottom of the box, once the corners are removed and the sides are folded up.</h3>

The area of the bottom of the box is calculated as:

Area = New length * New width

This gives

Area = (7 - 2x) * (4 - 2x)

Rewrite as:

A(x) = (7 - 2x) * (4 - 2x)

<h3>Part 3: Set up an equation in standard form that will help you find the size (x)</h3>

The area is given as:

Area = 16

So, we have:

(7 - 2x) * (4 - 2x) = 16

Expand

28 - 14x - 8x + 4x^2 = 16

Rewrite as

4x^2 - 14x - 8x + 28 - 16 = 0

Evaluate the like terms

4x^2 - 22x + 12= 0

<h3>Part 3: Solve this equation and take note of any extraneous solutions</h3>

We have:

4x^2 - 22x + 12= 0

Expand the equation

4x^2 - 24x - 2x + 12 = 0

Factorize the equation

4x(x - 6) - 2(x - 6) = 0

Factor out x - 6

(4x - 2)(x - 6) = 0

Solve for x

x = 0.5 or x = 6

The value of x = 6 is too big for the dimensions of the box.

So, x = 6 is an extraneous solution for the equation

Hence, the size of the corner you need to cut in order for your box to have this area is 0.5 inches

Read more about areas at:

brainly.com/question/24487155

#SPJ1

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