Answer:
it's (6,0) I can't explain though
Answer: The answer is (A) ∠T.
Step-by-step explanation: Given that the polygon ABCDE is congruent to the polygon TVSRK. We are to find the corresponding angle of ∠EAB.
In the two polygons, the corresponding vertices are
A ⇒ T
B ⇒ V
C ⇒ S
D ⇒ R
E ⇒ K.
Therefore, ∠EAB, which is ∠A will correspond to ∠T.
Thus, the correct option is (A) ∠T.
Scalene I believe. Hope this helps!
Answer:
1. 3sqrt(2)
Choice C
2. 2sqrt(3)
Choice D
Step-by-step explanation:
1. sqrt(x+3)
sqrt(15+3)
sqrt(18)
sqrt(9*2)
sqrt(9)sqrt(2)
3sqrt(2)
Choice C
2. 6/sqrt(x)
6/sqrt(3)
no radicals in the denominator, multiply by 1 in the form of the radical
6/sqrt(3) * sqrt(3)/sqrt(3)
6sqrt(3)/ (sqrt(3)*sqrt(3))
6sqrt(3)/3
2sqrt(3)
Choice D