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pickupchik [31]
3 years ago
13

What is the answer in long division 28÷8

Mathematics
2 answers:
AfilCa [17]3 years ago
8 0
3.5 us the answer to 28÷8
Mars2501 [29]3 years ago
3 0
The answer in long division would be 3 and a half

in fraction form: 3 1/2
in decimal form: 3.5 or 3.50
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What number is divisible by both 85 and 51
Vitek1552 [10]
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85/17 is 5 and 51/17 is 3
7 0
3 years ago
Read 2 more answers
Solve the equation. Then check your solution.
UNO [17]
<h3>Solve the equation. Then check your solution. </h3><h3>1.6a = -9.12 </h3>

Answer: b) -5.7

Step-by-step explanation:

<em>To solve this equation for the variable a, we have to clear the variable a, dividing both sides of the equation by the coefficient of the variable a.  </em>

a = -9.12/1.6 = -5.7

Answer: b) -5.7

<h2><em>Spymore</em></h2>
4 0
3 years ago
Given the figure below, find the values of x and z.<br> X=<br> Z=<br> (11x - 93)<br> H<br> 116<br> X
Marrrta [24]

Answer:

x = 19

z = 64

Step-by-step explanation:

Angles (11x - 93)° and 116° are vertical angles, so their measures are equal.

11x - 93 = 116

11x = 209

x = 19

Angles z° and 116° are a linear pair, so they are supplementary, and their measures have a sum of 180°

z + 116 = 180

z = 64

6 0
1 year ago
. If RST - UVW, find mZW.<br> S<br> 85<br> 48°<br> R<br> TU<br> W
Advocard [28]

Answer:

47°

Step-by-step explanation:

if it is the same, then the angles are the same

180 - 85 - 48 = 47

4 0
3 years ago
I need help plz. Its DeMoivres Theorem
vagabundo [1.1K]

\bf \qquad \textit{power of two complex numbers} \\\\\ [\quad r[cos(\theta)+isin(\theta)]\quad ]^n\implies r^n[cos(n\cdot \theta)+isin(n\cdot \theta)] \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ z=\stackrel{a}{-1}\stackrel{b}{-\sqrt{3}~i}~~ \begin{cases} r=\sqrt{a^2+b^2}\\ \theta =tan^{-1}\left( \frac{b}{a} \right)\\[-0.5em] \hrulefill\\ r=\sqrt{(-1)^2+(\sqrt{3})^2}\\ \qquad \sqrt{4}\\ \qquad 2\\ \theta =tan^{-1}\left( \frac{-\sqrt{3}}{-1} \right)\\\\ \qquad \frac{4\pi }{3} \end{cases}

\bf z=2\left[ cos\left( \frac{4\pi }{3} \right) -i~sin\left( \frac{4\pi }{3} \right)\right]\implies z^6=\left[ 2\left[ cos\left( \frac{4\pi }{3} \right) -i~sin\left( \frac{4\pi }{3} \right)\right] \right]^6 \\\\\\ z^6=2^6\left[ cos\left( 6\cdot \frac{4\pi }{3} \right) -i~sin\left( 6\cdot \frac{4\pi }{3} \right)\right]\implies z^6=64[cos(8\pi )-i~sin(8\pi )] \\\\\\ z^6=64[(-1)-i~(0)]\implies z^6=\stackrel{\stackrel{a}{\downarrow }}{-64}~~\stackrel{\stackrel{b}{\downarrow }}{-0i}

4 0
4 years ago
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