All categories

3 years ago

Help worth 25 points

Mathematics

2 answers:

mrs_skeptik [129]3 years ago

7 0

1 is PQR and RQP
2 is ABC and CBA
3 is STU and UTS

BigorU [14]3 years ago

6 0

1) <PQR or <RQP
2)<ABC or <CBA
3) <STU or <UTS
hope this helps
any question plz contact before reporting thx

You might be interested in

The length of a rectangle is 5 m less than twice the width, and the area is 33 m. Find the dimensions of the rectangle.

MrMuchimi

Check the picture below

it can't be -3... since is width unit, so it has to be the other

and recall that length = 2w - 5

7 0

3 years ago

Read 2 more answers

What is the value of 1.2^2

sveticcg [70]

Value of 1.2^2=1.44
value of 2^3+17-3*4=8+17-12=13
value of 9^2/3^3= 81/27=3

7 0

3 years ago

A. Steven wrote an expression with 2 terms. The second term, which is the whole number 7, is subtracted from the first term. The

bulgar [2K]

Answer:

Part a)

Steve's expression is $2(2x+5)^{2}-7$

For x=3, the expression is equal to $235$

Part b)

Jasmine's expression is

$(3x^{2})+(25x)$

For x=2, the expression is equal to $62$

Step-by-step explanation:

Part a)

Let

n-----> the first term

The expression is

$(n-7)$

$n=2(2x+5)^{2}$

substitute

Steve's expression is

$2(2x+5)^{2}-7$

Evaluate for x=3

$2(2(3)+5)^{2}-7=242-7=235$

Part b)

Let

n-----> the first term

Jasmine's expression is

$(3x^{2})+(25x)$

Evaluate for x=2

$(3(2)^{2})+(25(2))=12+50=62$

4 0

3 years ago

Add - 3/x + 7y/x . <br> -4y/2x<br> -3 + 7y/x<br> - 10y/x<br> -3 + 7y/2x

yanalaym [24]

Answer:

$-\frac{3}{x} + \frac{7y}{x} = \frac{-3+ 7y}{x}$

Step-by-step explanation:

Given

$-\frac{3}{x} , \frac{7y}{x}$

Required

Add

The statement can be interpreted as:

$-\frac{3}{x} + \frac{7y}{x}$

Take LCM

$-\frac{3}{x} + \frac{7y}{x} = \frac{-3+ 7y}{x}$

3 0

2 years ago

. Among all the income tax forms filed in a certain year, the mean tax paid was $2000, and the standard deviation was $500. In a

Anarel [89]

Answer:

a) 0.8413

b) 0.6293

Step-by-step explanation:

Data provided:

Mean tax paid = $2000

Standard deviation = $500

Sample size, n = 625

n=625

Now,

a) P( average tax paid on the sample forms is greater than $1980)

⇒ P(X > 1980)

⇒ $P(\frac{(X-mean)}{\frac{s}{\sqrt n}})$

⇒ $P(\frac{(1980-2000)}{\frac{500}{\sqrt{625}}})$

⇒ P(Z > -1)

= 0.8413 (From standard normal table)

b) P(more than 60 of the sampled forms have a tax of greater than $3000)

given: p = 10% = 0.1

Now, by using CLT

mean = n × p

= 625 × 0.1

= 62.5

Standard deviation, s = $\sqrt{n\times p\times(1-p)}$

= $\sqrt{625\times0.1\times(1-0.1)}$

= 7.5

Thus,

P(X > 60)

= $P(\frac{(X-mean)}{s} > \frac{(60-62.5)}{7.5})$

= P(Z > -0.33)

= 0.6293 (From standard normal table)

4 0

3 years ago