<u>ANSWER</u>
The number of lemonade in the can is 4. So we write,
![n(L)=4](https://tex.z-dn.net/?f=n%28L%29%3D4)
The number of apple in the can is 3. So we write,
![n(A)=3](https://tex.z-dn.net/?f=n%28A%29%3D3)
The number of iced tea in the can is 5. So we write,
.
The total number of drinks in the can,
.
Probability of selecting a can of an iced tea,
![P(I)=\frac{n(I)}{n(S)}](https://tex.z-dn.net/?f=P%28I%29%3D%5Cfrac%7Bn%28I%29%7D%7Bn%28S%29%7D)
![P(I)=\frac{5}{12}](https://tex.z-dn.net/?f=P%28I%29%3D%5Cfrac%7B5%7D%7B12%7D)
Since he selected the first one and gave it to his friend, the samples space as well as the number of iced tea will reduce by 1.
Probability of selecting a can of an iced tea again is,
.
Therefore probability of selecting 2 cans of an iced tea is
![P(2 \:cans of\: iced \:tea)=\frac{5}{12} \times \frac{4}{11}](https://tex.z-dn.net/?f=P%282%20%5C%3Acans%20of%5C%3A%20iced%20%5C%3Atea%29%3D%5Cfrac%7B5%7D%7B12%7D%20%5Ctimes%20%5Cfrac%7B4%7D%7B11%7D)
![P(2 \:cans of\: iced \:tea)=\frac{20}{132}](https://tex.z-dn.net/?f=P%282%20%5C%3Acans%20of%5C%3A%20iced%20%5C%3Atea%29%3D%5Cfrac%7B20%7D%7B132%7D)
![P(2 \:cans of\: iced \:tea)=\frac{5}{33}](https://tex.z-dn.net/?f=P%282%20%5C%3Acans%20of%5C%3A%20iced%20%5C%3Atea%29%3D%5Cfrac%7B5%7D%7B33%7D)
.
The correct answer is option C
For this case we have the following function:
f (t) = -16t2 + 32t + 384
By definition we have to:
The average rate of change:
AVR = (f (t2) - f (t1)) / (t2 - t1)
Where,
For t1 = 4
f (4) = -16 * (4) ^ 2 + 32 * (4) + 384
f (4) = 256
For t2 = 6
f (6) = -16 * (6) ^ 2 + 32 * (6) + 384
f (6) = 0
Substituting values we have:
AVR = (0 - 256) / (6 - 4)
AVR = -128
Answer:
The average rate of change of f (t) from t = 4 seconds to t = 6 seconds is -128 feet per second.
C.
No value of x has two values of y, thus it is a one-to-one function.
That would be 21 my friend
Answer:
Uhhhhhhhhh 25?
Step-by-step explanation: