Since it’s in the tenths place it’s 50
We find the area of the total square which is 8in • 8in=64in^2 . Now we find the area of the small quadrilateral which is 4in•4in=16 in^2.
Now we subtract the area of the small quadrilateral from the big quadrilateral’s area 64in^2 -16in^2 leaving us with the are of 48in^2 of the figure
Notice that the reflection is over a line of the form x=constant; in this case, the y-coordinate of the reflected point stays the same while the x-coordinate changes as expressed by the transformation below
Hence, in our case
Transform points N, M, and O accordingly,
<h2>Therefore, the answer is the first option (top to bottom)</h2>
This would be 3x + y = 0.
I hope this helps!
Answer:
its c 2b(12 - 17a)
Step-by-step explanation:
