<h3>Given</h3>
A regular polygon with area 500 ft² and apothem 10 ft
Cost of fence is $7.95 per ft
<h3>Find</h3>
Part III The cost of fence around an area scaled to 60 times the size
<h3>Solution</h3>
You don't want to think too much about this, because if you do, you find the regular polygon has 3.087 sides. The closest approximation, an equilateral triangle, will have an area of 519.6 ft² for an apothem of 10 ft.
For similar shapes of scale factor "s", the larger shape will have an area of s² times that of the smaller one. Here, it appears the area scale factor s² is 60, so the linear scale factor is
... s² = 60
... s = √60 ≈ 7.7460
The perimeter fence of the 500 ft² area is presumed to be 100 ft long (twice the area of the polygon divided by the apothem—found in Part I), so the perimeter fence of the industrial farm is ...
... (100 ft)×7.7460 = 774.60 ft
and the cost to construct it is
... ($7.95/ft)×(774.60 ft) ≈ $6158
= 11( - 1)
Step-by-step explanation:
The sum to n terms of a geometric sequence is
=
where a₁ is the first term and r the common ratio
Here a₁ = 11 and r = = = 2 , then
= = 11 ( - 1)
3 litres I think
Because it 8 inches is pretty tall
Answer:
Last one is one of the answers
Step-by-step explanation:
3(x+4)=-24
= 3x +12=-24
Step-by-step explanation:
The option is C
= 1/ 2^20 • z^15
Hope it will help :)
