If an object is dropped from a tall building and hits the ground 3.0 s. later, what is the magnitude of the object's displacemen
1 answer:
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Answer:
1027.2 m
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration due to gravity = 32.2 ft/s
The height the tomato would fall is 450+577.2 = 1027.2 m
Explanation:
It is given that,
Velocity of particle 1, u₁ = 10 m/s
Velocity of particle 2, u₂ = 5 m/s
Let v₁ and v₂ are the final speed of both particles after the collision. Applying the conservation of momentum as :
......................(1)
For an elastic collision, the coefficient of restitution is equal to 1 as :
................(2)
On solving equation (1) and (2), we get,
So, the speeds of particle 1 and particle 2 after the collision is 5 m/s and 10 m/s respectively. Hence, this is the required solution.