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laila [671]
3 years ago
11

How are balanced & unbalanced forces related to net force?

Physics
1 answer:
Levart [38]3 years ago
4 0

Answer:

An unbalanced force (net force) acting on an object changes its speed and/or direction of motion. ... A net force = unbalanced force. If however, the forces are balanced (in equilibrium) and there is no net force, the object will not accelerate and the velocity will remain constant.

Explanation:

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A force acting over a large area will exert less pressure per square inch than the same force acting over a smaller area.
babunello [35]

Answer:

True

Explanation:

Pressure is defined as:

p=\frac{F}{A}

where

F is the magnitude of the force perpendicular to the surface

A is the surface

Therefore, pressure is inversely proportional to the area of the surface:

p\propto \frac{1}{A}

this means that, assuming that the forces in the two situations (which have same magnitude) are both applied perpendicular to the surface, the force exerted over the smaller area will exert a greater pressure. Hence, the statement"

<em>"A force acting over a large area will exert less pressure per square inch than the same force acting over a smaller area"</em>

is true.

8 0
3 years ago
1. Although the sun is shining, it is a little chilly today at the beach. You look at your portable thermometer, which says it's
Ganezh [65]

Answer:

(10°C × 9/5) + 32 = 50°F

10°C + 273.15 = 283.15K

Explanation:

3 0
3 years ago
Calculate the force generated by a car that hits the wall at an
Makovka662 [10]

This is a defective question. It was WRITTEN by someone who is unclear on the concepts.  DON'T try and answer it.

It's trying to get us to use Newton's second law ... F = m • a.

But that only tells us how much force must act ON THE CAR in order to accelerate it. (45 kg) • (4 m/s^2) = 180 newtons.

This is NOT the force exerted BY the car when it hits something. THAT force depends on its speed WHEN it hits, AND how long it takes for the wreckage to actually come to rest, AND how hard or soft the wall is.

DON'T try to answer this question. Your answer will be wrong, you won't understand why, and the teacher you try to argue with probably won't either.

============================================

More explanation:

Think about jumping off of a ladder in your back yard.  Several times.

Your mass is the same every time.  Your acceleration is the same every time . . . 9.8 m/s² down, the acceleration of Earth gravity, every time.

BUT ...

-- I'll bet you would rather land on wood than on concrete. The force of landing would be less.

-- I'll bet you would rather land on dirt than on wood. The force of landing would be less.

-- I'll bet you would rather land on grass than on dirt. The force of landing would be less.

-- I'll bet you would rather land on a pile of blankets than on dirt. The force of landing would be less.

-- I'll bet you would rather land on a trampoline than on a pile of blankets. The force of landing would be less.

-- I'll bet you would rather jump from a short ladder than from a tall one.  Your speed would be less when you landed, and the force of landing would be less.

==> Your mass is the SAME every time, and your acceleration is the SAME every time.  But the force when you hit is DIFFERENT every time.

The mass and acceleration of the car DON'T tell us the force of the hit when the car hits a wall.  

6 0
3 years ago
Please tell me why the answer is zero
Oduvanchick [21]

This question is checking to see whether you understand the meaning
of "displacement".

Displacement is a vector: 

-- Its magnitude (size) is the distance between the start-point and
the end-point, no matter what route might have been followed along
the way.

-- Its direction is the direction from the start-point to the end-point.

Talking about the Earth's orbit around the sun, we can forget about
the direction of the displacement, and just talk about its magnitude
(size).

If we pretend that the sun is not moving and dragging the whole
solar system along with it, then what do we see the Earth doing
in one year ? 
We mark the place where the Earth is at the stroke of midnight
on New Year's Eve.  Then we watch it as it swings around through
this gigantic orbit, all the way around the sun, and in a year, it's back
to the same point that we marked ! 

So what's the magnitude of the displacement in exactly one year ?
It's the distance between the start-point and the end-point.  But the
Earth came back to the same place it started from, so there's no
separation at all between the start-point and the end-point. 
The Earth covered a huge distance in that year, but the displacement
is zero.

5 0
3 years ago
Read 2 more answers
Convert the following measurements. Only type numbers and decimals into the answer boxes:
ivolga24 [154]

Answer:

2m 4m2Explanation:rteji3ujnrej

6 0
3 years ago
Read 2 more answers
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