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3 years ago

11

A circular coil of wire of 200 turns and diameter 6 cm carries a current of 7 A. It is placed in a magnetic field of 0.90 T with

the plane of the coil making an angle of 30° with the magnetic field. What is the torque on the coil?

1 answer:

Brums [2.3K]3 years ago

7 0

Answer:

3.08 Nm

Explanation:

N = 200, diameter = 6 cm, radius = 3 cm, I = 7 A, B = 0.90 T, Angle = 30 degree

The angle made with the normal of the coil, theta = 90 - 30 = 60 degree

Torque = N I A B Sin Theta

Torque = 200 x 7 x 3.14 x 0.03 x 0.03 x 0.90 x Sin 60

Torque = 3.08 Nm

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The question is in the picture

Sedbober [7]

Answer:

e) 120m/s

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$t = \dfrac{v_0}{g}$

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