For a parabola that opens upward, it must be a quadratic equation whose coefficient of x2 is a positive number.
So, I'll say x2+5x+6.
Considering the hang time equation, it is found that Player 1 jumped 0.68 feet higher than Player 2.
<h3>What is the hang time equation?</h3>
The hang-time of the ball for a player of jump h is given by:

The expression can be simplified as:

For a player that has a hang time of 0.9s, the jump is found as follows:




h = 3.24 feet.
For a player that has a hang time of 0.8s, the jump is found as follows:




h = 2.56 feet.
The difference is given by:
3.24 - 2.56 = 0.68 feet.
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Answer:
x = 7, y = 2
Step-by-step explanation:
I assume it is 3/(x-7) + 2.
When x = 7, there is an asymptote because it is undefined.
When y = 2, there is also one, because 3/(x-7) is never 0.
These are the only ones.