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bagirrra123 [75]

3 years ago

8

Carl has three lengths of cable, 3/6 yard long, 1/4 yard long, and 1/3 yard long, which two pieces together make a length of 20/

24 yard?

1 answer:

iris [78.8K]3 years ago

7 0

First you should Simplify
$\frac{20}{24} = \frac{5}{6}$
$\frac{3}{6} + \frac{1}{3} = \frac{5}{6}$

Solution
1. Find the LCM between 6 and 3 which is 8
2. Times 3 and 6 to both sides of the equation respectively.
$\frac{3 \times 3}{18} + \frac{6 \times 1}{18}$
$\frac{9 + 6}{18} = \frac{15}{18}$
3. Simplify the answer by dividing by 3.

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noname [10]

Answer:

See below in bold.

Step-by-step explanation:

The cost of what he wants to buy = 4.25 + 0.89 + 10.99

= $16.13

a) He does have enough to buy everything.

b) He has 20 - 16.13 = $3.87 left over.

7 0

3 years ago

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Marta_Voda [28]

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4 0

2 years ago

On a coordinate plane, triangle A B C is shown. Point A is at (0, 0), point B is at (3, 4), and point C is at (3, 2). What is th

Elena L [17]

Answer:

The area of triangle for the given coordinates is 1.5 $\sqrt{4.6}$

Step-by-step explanation:

Given coordinates of triangles as

A = (0,0)

B = (3,4)

C = (3,2)

So, The measure of length AB = a = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, a = $\sqrt{(3-0)^{2}+(4-0)^{2}}$

Or, a = $\sqrt{9+16}$

Or, a = $\sqrt{25}$

∴ a = 5 unit

Similarly

The measure of length BC = b = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, b = $\sqrt{(3-3)^{2}+(2-4)^{2}}$

Or, a = $\sqrt{0+4}$

Or, b = $\sqrt{4}$

∴ b = 2 unit

And

So, The measure of length CA = c = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, c = $\sqrt{(3-0)^{2}+(2-0)^{2}}$

Or, c = $\sqrt{9+4}$

Or, c = $\sqrt{13}$

∴ c = $\sqrt{13}$ unit

Now, area of Triangle written as , from Heron's formula

A = $\sqrt{s\times (s-a)\times (s-b)\times (s-c)}$

and s = $\frac{a+b+c}{2}$

I.e s = $\frac{5+2+\sqrt{13}}{2}$

Or. s = $\frac{7+\sqrt{13}}{2}$

So, A = $\sqrt{(\frac{(7+\sqrt{13})}{2})\times ((\frac{(7+\sqrt{13})}{2})-5)\times (\frac{7+\sqrt{13}}{2}-2)\times (\frac{7+\sqrt{13}}{2}-\sqrt{13})}$

Or, A = $\sqrt{(\frac{(7+\sqrt{13})}{2})\times (\frac{(\sqrt{13}-3)}{2})\times (\frac{4+\sqrt{13}}{2})\times (\frac{7-\sqrt{13}}{2})}$

Or, A = $\frac{3}{2}$ × $\sqrt{1+\sqrt{13} }$

∴ Area of triangle = 1.5 $\sqrt{4.6}$

Hence The area of triangle for the given coordinates is 1.5 $\sqrt{4.6}$ Answer

7 0

3 years ago

Read 2 more answers

An empty cubical carton is side 7cm. Can you fill 1000 cubes of side 1cm in it ?

Shalnov [3]

An empty cubical carton of side 7cm has the volume:
7 x 7 x 7 = 343cm³

A cube of side 1cm has the volume:
1 x 1 x 1 = 1cm³

From this, we can see that a 1000 cubes of side 1cm has the volume:
1000 x 1cm³ = 1000cm³

But we know that the cubical carton of side 7cm only has a volume of 343cm³.

Since 1000cm³ > 343cm³,
you cant fill 1000 cubes of side 1cm in such a carton.

TL;DR
No

Hope this helps

8 0

2 years ago

Complete the function<br> table below for y= 4x + 5. (Look at the photo.)

Stolb23 [73]

Answer:

5, 25, 45

Step-by-step explanation:

okay so it goes like this, the number in the x colume X 4 + 5 so 0 X 4 = 0 + 5 = 5, 5 X 4 is 20 + 5 = 25 and 10 X 4 =40 + 5 = 45.

6 0

2 years ago