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bagirrra123 [75]
4 years ago
8

Carl has three lengths of cable, 3/6 yard long, 1/4 yard long, and 1/3 yard long, which two pieces together make a length of 20/

24 yard?
Mathematics
1 answer:
iris [78.8K]4 years ago
7 0
First you should Simplify
\frac{20}{24} = \frac{5}{6}
\frac{3}{6} + \frac{1}{3} = \frac{5}{6}


Solution
1. Find the LCM between 6 and 3 which is 8
2. Times 3 and 6 to both sides of the equation respectively.
\frac{3 \times 3}{18} + \frac{6 \times 1}{18}
\frac{9 + 6}{18} = \frac{15}{18}
3. Simplify the answer by dividing by 3.
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Can u please help me??
frez [133]

Answer:

<u>Given GP:</u>

  • tₙ = (1/3)ⁿ⁻¹

<u>We see that:</u>

  • t₁ = 1, r = 1/3

<u>Sum of  n terms:</u>

  • Sₙ = t₁(1 - rⁿ)/(1 - r)
  • Sₙ = [1 - (1/3)ⁿ] / (1 - 1/3) = [1 - (1/3)ⁿ] / (2/3) = 3/2 [1 - (1/3)ⁿ]
  • Sₙ = 3/2 [1 - (1/3)ⁿ]
3 0
3 years ago
What is the value of f-1(4)
scZoUnD [109]

Answer:

x=4 hope that helps I did it on my calculator story if it is wrong

5 0
3 years ago
X-16/x+6 = 3/5 its a proportion
kozerog [31]

Answer:

use khan academy

Step-by-step explanation:

3 0
3 years ago
Ardi and Lei are both travelling by train. Ardi's train travels 70 km in 35 minutes. Lei's train travels 585 km. It leaves at 9:
Leni [432]

Answer:

10 km/hr

Step-by-step explanation:

Average speed = Total distance travelled / Total time taken

Ardi:

Total distance travelled = 70 km

Total time taken = 35 minutes = 35/60 hour

Average speed = Total distance travelled / Total time taken

= 70 km ÷ 35/60 hr

= 70 × 60/35

= 4,200/35

= 120 km/hr

Lei:

Total distance travelled = 585 km Total time taken = 9:05 - 13:35 = 4 hours 30 minutes

= 4.5 hours

Average speed = Total distance travelled / Total time taken

= 585 km / 4.5 hours

= 130 km/hr

Difference, in km/h, between the average speed of their trains = Lei's train - Ardi's train

= 130 km/hr - 120 km/hr

= 10 km/hr

3 0
3 years ago
Joni has two cats in the yard, Stephen and Graham. If both animals gained 20 pounds, Stephen would be 25% heavier than Graham. F
tresset_1 [31]

Answer:

Stephen weighs 80 lbs

Graham weighs 60 lbs

Step-by-step explanation:

Let Stephen the cat = S

Let Graham the cat = G

25% heavier = 125% = 125/100 = 1.25

50% heavier = 150% = 150/100 = 1.5

If both animals gained 20 lbs, S would be 25% heavier than G:

    S + 20 = 1.25(G + 20)  

⇒          S = 1.25(G + 20) - 20

⇒          S = 1.25G + 5

If both animals lost 20 lbs, S would be 50% heavier than G:

    S - 20 = 1.5(G - 20)  

⇒          S = 1.5(G - 20) + 20

⇒          S = 1.5G - 10

Equate both equations for S, and solve for G:

                 S = S

⇒ 1.25G + 5 = 1.5G - 10

⇒     -0.25G = -15

⇒              G = 60

Substitute found value for G into one of the equations for S and solve for S:

    S = 1.5G - 10  

⇒  S = 1.5 x 60 - 10

⇒  S = 90 - 10

⇒  S = 80

Stephen weighs 80 lbs

Graham weighs 60 lbs

6 0
3 years ago
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