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bagirrra123 [75]
3 years ago
8

Carl has three lengths of cable, 3/6 yard long, 1/4 yard long, and 1/3 yard long, which two pieces together make a length of 20/

24 yard?
Mathematics
1 answer:
iris [78.8K]3 years ago
7 0
First you should Simplify
\frac{20}{24} = \frac{5}{6}
\frac{3}{6} + \frac{1}{3} = \frac{5}{6}


Solution
1. Find the LCM between 6 and 3 which is 8
2. Times 3 and 6 to both sides of the equation respectively.
\frac{3 \times 3}{18} + \frac{6 \times 1}{18}
\frac{9 + 6}{18} = \frac{15}{18}
3. Simplify the answer by dividing by 3.
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dolphi86 [110]

radius = 48 feet

a = πr²

a = 3.14(48)²

a = 3.14 x 2304

a = 7234.56 feet

a = 7234.6 feet

3 0
2 years ago
A car rental company rented out 8 cars in its first month. The number of cars it rented doubled each month. What was the total n
skad [1K]
The total number of cars rented for the first 5 months is
8 + 16 + 32 + 64 + 128 = 248
6 0
2 years ago
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Ricky race $640 in a charity walk last year this year he raised 15% more than he raised last year how much money did Ricky raise
Mashutka [201]
He raised $736.

One way is to multiply 640 x .15 = 96
Add 96 + 640 = 736
8 0
2 years ago
Complete the assignment on a separate sheet of paper<br><br> Please attach pictures of your work.
Irina18 [472]

Answer:

<u>TO FIND :-</u>

  • Length of all missing sides.

<u>FORMULAES TO KNOW BEFORE SOLVING :-</u>

  • \sin \theta = \frac{Side \: opposite \: to \: \theta}{Hypotenuse}
  • \cos \theta = \frac{Side \: adjacent \: to \: \theta}{Hypotenuse}
  • \tan \theta = \frac{Side \: opposite \: to \: \theta}{Side \: adjacent \: to \: \theta}

<u>SOLUTION :-</u>

1) θ = 16°

Length of side opposite to θ = 7

Hypotenuse = x

=> \sin 16 = \frac{7}{x}

=> \frac{7}{x} = 0.27563......

=> x = \frac{7}{0.27563....} = 25.39568..... ≈ 25.3

2) θ = 29°

Length of side opposite to θ = 6

Hypotenuse = x

=> \sin 29 = \frac{6}{x}

=> \frac{6}{x} = 0.48480......

=> x = \frac{6}{0.48480....} = 12.37599..... ≈ 12.3

3) θ = 30°

Length of side opposite to θ = x

Hypotenuse = 11

=> \sin 30 = \frac{x}{11}

=> \frac{x}{11} = 0.5

=> x = 0.5 \times 11 = 5.5

4) θ = 43°

Length of side adjacent to θ = x

Hypotenuse = 12

=> \cos 43 = \frac{x}{12}

=> \frac{x}{12} = 0.73135......

=> x = 12 \times 0.73135.... = 8.77624.... ≈ 8.8

5) θ = 55°

Length of side adjacent to θ = x

Hypotenuse = 6

=> \cos 55 = \frac{x}{6}

=> \frac{x}{6} = 0.57357......

=> x = 6 \times 0.57357.... = 3.44145.... ≈ 3.4

6) θ = 73°

Length of side adjacent to θ = 8

Hypotenuse = x

=> \cos 73 = \frac{8}{x}

=> \frac{8}{x} = 0.29237......

=> x = \frac{8}{0.29237.....} = 27.36242..... ≈ 27.3

7) θ = 69°

Length of side opposite to θ = 12

Length of side adjacent to θ = x

=> \tan 69 = \frac{12}{x}

=> \frac{12}{x} = 2.60508......

=> x = \frac{12}{2.60508....}  = 4.60636.... ≈ 4.6

8) θ = 20°

Length of side opposite to θ = 11

Length of side adjacent to θ = x

=> \tan 20 = \frac{11}{x}

=> \frac{11}{x} = 0.36397......

=> x = \frac{11}{0.36397....}  =30.22225.... ≈ 30.2

5 0
2 years ago
Arthur is saving money to buy a used car in 8 months. The car costs $2,180. Arthur plans to start with an initial deposit and th
Zolol [24]

The minimum initial deposit Arthur must make is $ 4.24.

Since Arthur is saving money to buy a used car in 8 months, and the car costs $ 2,180, and Arthur plans to start with an initial deposit and then deposit 25% more than the previous month until he has enough money to buy the car, to determine what is the minimum initial deposit Arthur must make the following calculation should be performed:  

  • X x 1.25 x 1.56 x 1.95 x 2.44 x 3.05 x 3.81 x 4.76 = 2180
  • 514.10X = 2180
  • X = 2180 / 514.10
  • X = 4.24

Therefore, the minimum initial deposit Arthur must make is $ 4.24.

Learn more about maths in brainly.com/question/25749130

6 0
2 years ago
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