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2 years ago

9

How to graph the first derivative of this function

1 answer:

borishaifa [10]2 years ago

7 0

From -co to 0, the derivative is y=-2x and its domain is (-co,4]. Then y=-(x-2)/2 + 6 from (4,co)

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7. The largest of the Great Pyramids in Egypt was built with a square base,

strojnjashka [21]

Answer:

Difference between the original and current volumes = 4013140.30 cubic feet

Step-by-step explanation:

Largest pyramid has the square base with one edge = 754 feet

Area of the square base = (Side)²

= (754)²

= 568516 square feet

Volume of the pyramid = $\frac{1}{3}(\text{Area of the base})(\text{Height})$

= $\frac{1}{3}\times 568516\times 481$

= 91152065.3 cubic feet

After erosion,

Area of the base = (745)² = 555025 square feet

Volume of the pyramid = $\frac{1}{3}(555025)(471)$

= 87138925 cubic feet

Difference between the original and current volumes of the pyramid

= 91152065.30 - 87138925

= 4013140.30 cubic feet

5 0

3 years ago

Adult tickets to a play cost $24. Tickets for children cost $18. Tickets for a group of 13 people cost $282. Write and solve a s

Elan Coil [88]

Let number of Adult ticket be x
and number of Child ticket be y
so
$282 = $24x + $18y.
:)

4 0

3 years ago

Read 2 more answers

PLEASE HELP ASAP. I NEED TO KNOW NOW

Vitek1552 [10]

Answer:

the answer is x1 = -4- square root of 23 x2= -4+ square root of 23

8 0

2 years ago

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I'm doing Big Ideas Geometry and the question is, "Find the distance between a(-4,-8) and b(-1,4). Could you please show your wo

Lina20 [59]

Answer:

Step-by-step explanation:The formula is the long root of (x2-x1)² + (y2-y1)², you have -1 to be the value of x2 and -4 is the value of x1 while 4 is the value of y2 and -8 is the value of y1 therefore (-1+4)²+(4+8)² = (3)²+(12)²= √9+12=√153

5 0

1 year ago

Using the following equation, find the center and radius of the circle. You must show all work and calculations to receive credi

zalisa [80]

Answer:

The circle is of radius $5$ and is centered at $(-1,\, -2)$ .

Step-by-step explanation:

Equation for a circle of radius $r$ ( $r > 0$ ) and center $(a,\, b)$ :

$(x - a)^{2} + (y - b)^{2} = r^2$ .

Expand and rearrange to obtain an equivalent equation:

$\left(x^2 - 2\, a\, x + a^{2}\right) + \left(y^2 - 2\, b\, y + b^2\right) = r^{2}$ .

$x^2+ (-2\, a)\, x + y^2 + (-2\, b)\, y = r^2 - (a^2 + b^2)$ .

Compare this equation with the equation of the circle in this question:

Coefficient of the $x$ term: $2$ in the original equation, $(-2\, a)$ in the proposed equation.
Coefficient of the $y$ term: $4$ in the original equation, $(-2\, b)$ in the proposed equation.
Constant term: $20$ in the original equation, $\left(r^2 - \left(a^2 + b^2 \right)\right)$ in the proposed equation.

Assume that the proposed equation matches the equation from the question. Each of the coefficients should match.

From the coefficient of the $x$ term and the $y$ term: $a = -1$ and $b = -2$ .

Hence, the center of this circle is at $(a,\, b) = (-1,\, -2)$ .

The constant term of the two equations should also match: $\left(r^2 - \left(a^2 + b^2 \right)\right) = 20$ .

$\left(r^2 - \left((-1)^2 + (-2)^2 \right)\right) = 20$ .

$r^2 = 25$ .

$r = 5$ (given that radius $r > 0$ .)

Hence, the radius of this circle would be $5$ .

5 0

2 years ago

Read 2 more answers