(a)
Q1, the first quartile, 25th percentile, is greater than or equal to 1/4 of the points. It's in the first bar so we can estimate Q1=5. In reality the bar includes values from 0 to 9 or 10 (not clear which) and has around 37% of the points so we might estimate Q1 a bit higher as it's 2/3 of the points, say Q1=7.
The median is bigger than half the points. First bar is 37%, next is 22%, so its about halfway in the second bar, median=15
Third bar is 11%, so 70% so far. Four bar is 5%, so we're at the right end of the fourth bar for Q3, the third quartile, 75th percentile, say Q3=40
b
When the data is heavily skewed left like it is here, the median tends to be lower than the mean. The 5% of the data from 80 to 120 averages around 100 so adds 5 to the mean, and 8% of the data from the 60 to 80 adds another 5.6, 15% of the data from 40 to 60 adds about 7.5, plus the rest, so the mean is gonna be way bigger than the median of around 15.
8x3.5= ? That’s gonna be your answer.
Answer:
c 2/3
Step-by-step explanation:
there are six sides to a die. Therefore when you roll you have a 1 in 6 of getting a specific number 1/6 . Since you only want numbers greater than 2 your odds are now 4/6. Remove 1 and 2 from the equation and there are now only 4 out of 6 correct numbers. 4/6
4/6 can be reduce to 2/3rds. That is your answer
Answer:
it's B ==35
Step-by-step explanation:
Answer:
49<em>r</em>
Step-by-step explanation:
Written out it would be
49 x <em>r</em> = ?
But because mathmetitians like to write quickly, we say the answer above.
Key words are the product of 49 and the length of rope. So that means we are multipling which makes 49<em>r</em> the correct expression.
