2 years ago

I need to know how to do number 20

Mathematics

1 answer:

zimovet [89]2 years ago

6 0

$(x^4y^3)^2=(x^4)^2(y^3)^2=x^{4\cdot2}y^{3\cdot2}=x^8y^6\\\\Used:\\\\(a\cdot b)^n=a^n\cdot b^n\\\\(a^n)^m=a^{n\cdot m}$

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You have decided to purchase a car for $19,000. The credit union requires a 10% down payment and will finance the balance with a

Lady_Fox [76]

<h2>○=> <u>Correct option</u> :</h2>

$\color{plum} \bold{ \tt \: \bold{C. \$20,652.00}}$

<h3>○=> <u>Steps to derive correct option</u> :</h3>

Selling price of a car = $19,000

Percentage of sales tax in the city = 8.3%

Sales tax :

$= \tt \frac{8.3}{10 \times 100} \times 1900$

$= \tt \frac{8.3 \times 19000}{1000}$

$= \tt \frac{1577000}{1000}$

$\color{plum} = \tt \$1577$

Thus, the sales tax on the car = $1577

Cost of license and title = $75

Total price of car :

= Cost price of car + Sales tax + cost of license/title

$= \tt19000 + 1577 + 75$

$\color{plum} = \tt \$20652$

Thus, the total purchase price of the car = $20,652.00

Therefore, the correct option is <em>(C) $20,652.00</em>

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2 years ago

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FromTheMoon [43]

Answer:

A is 7 and B is

Step-by-step explanation:

A: 3x2 is 6+1 is 7

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2 years ago

Use the guess and check method <br> 4(x+2)+2=14

Pani-rosa [81]

Answer:

Step-by-step explanation:

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2 years ago

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Two positive, consecutive, odd integers have a product of 143. set up an equation to then solve for the integers.

mixer [17]

Answer:

Step-by-step explanation:

Let (2n-1) and (2n+1) be the consecutive, odd numbers.

(2n-1)(2n+1) = 143

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4n² = 144

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n = 6

2n-1 = 11

2n+1 = 13

The numbers are 11 and 13.

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2 years ago

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Graph of the equation y=x+3 is shown

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