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Feliz [49]
3 years ago
7

Which car traveled at the slowest rate?

Mathematics
2 answers:
Viktor [21]3 years ago
5 0
(D) traveled at the slowest rate.
mixas84 [53]3 years ago
5 0

Answer:

D) 800 miles in 12 hours was the slowest



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What is the factored form of 125a6-64?
iogann1982 [59]

Answer:

(5a^2-4)*(25a^4+20a^2+16)

Step-by-step explanation:

7 0
3 years ago
Plz help and get 10 points plz help me emergency
emmainna [20.7K]
I believe that 1 cup has 8 fluid ounces, and for 3 it is 24 fluid ounces, and for 5 it is 40 fl oz, for 7 it is 56 fl oz

For gallons the first one is 16, for 5 it is 20, for 6 it is 24, and for 7 it is 28.

For the gallon with pint measurement, the first one is 32 pt, the second one is 40, the third one is 48, and the fourth one is 56.


For quarts the first one is 2 pt, the second is 4 pt, the third one is 6 pt, and the fourth one is 8 pt.




6 0
3 years ago
$149 guitar; 29% discount​
Vikki [24]
Divide number of guitars by 100% and multiply into discount given



149/100 x 29

1.49 x 29

43.21



$43.21 had been removed

Therefore $105.79 is the guitar cost after discount



Hope it was useful ☻


5 0
3 years ago
A customer brings a box with a mix of integers as inputs to a function machine. She wants you to program a function machine so t
Natasha_Volkova [10]

Answer:

The manager did not make a good suggestion.

Any values of x that are less than or equal to -20 will result in a non-negative output and will not meet the customer's needs.

7 0
3 years ago
Sin2x-sin2xcos2x=sin4x
yaroslaw [1]

It looks like the given equation is

sin(2x) - sin(2x) cos(2x) = sin(4x)

Recall the double angle identity for sine:

sin(2x) = 2 sin(x) cos(x)

which lets us rewrite the equation as

sin(2x) - sin(2x) cos(2x) = 2 sin(2x) cos(2x)

Move everything over to one side and factorize:

sin(2x) - sin(2x) cos(2x) - 2 sin(2x) cos(2x) = 0

sin(2x) - 3 sin(2x) cos(2x) = 0

sin(2x) (1 - 3 cos(2x)) = 0

Then we have two families of solutions,

sin(2x) = 0   or   1 - 3 cos(2x) = 0

sin(2x) = 0   or   cos(2x) = 1/3

[2x = arcsin(0) + 2nπ   or   2x = π - arcsin(0) + 2nπ]

… … …   or   [2x = arccos(1/3) + 2nπ   or   2x = -arccos(1/3) + 2nπ]

(where n is any integer)

[2x = 2nπ   or   2x = π + 2nπ]

… … …   or   [2x = arccos(1/3) + 2nπ   or   2x = -arccos(1/3) + 2nπ]

[x = nπ   or   x = π/2 + nπ]

… … …   or   [x = 1/2 arccos(1/3) + nπ   or   x = -1/2 arccos(1/3) + nπ]

7 0
3 years ago
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