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Anna007 [38]
2 years ago
15

Teresa is in need for help ;-; pls help her! (lolllllllllllllllllllllllllllllllllllllllllllllllllll)

Mathematics
2 answers:
kipiarov [429]2 years ago
6 0

Answer:

90 i said it first so i smart

Step-by-step explanation:

nata0808 [166]2 years ago
4 0
90

the answer is 90 but the answer i give has to be over 20 characters so i'm typing random things. have a good day:)
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elixir [45]
12^2+x^2=15^2
144+x^2=225
- 144 -144
=81= 9
X=9
7 0
2 years ago
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Please help 50 points <br><br> What is the fractional form of
Mumz [18]

Answer:

it's option A .............

8 0
3 years ago
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Urgenttttt please I need it fast​
dolphi86 [110]

Answer:

Below in bold.

Step-by-step explanation:

c) 3 x (9^2)^3/4 x ((81^3)^5/6

= 3 x 81^3/4 x 81^15/6

= 3 x 81^(3/4 + 15/6)

= 3 x 81^13/4

= 3 x 3^13

= 3^14

= 4,782,969.

f) (5x^-1y^2)^-2 / (25 x^2 y - 1)^2

=  5^-2 x^2y^-4 / 625 x^4y^-2

=  5^-2 x^-2 y^-2 / 5^4

= 5^-6 x^-2y^-2

= 0.000064x^-2y^-2.

5 0
2 years ago
A box of 42 chocolates contains milk and dark chocolates in the ratio of 3:4. How many chocolates of each type there are?
Elza [17]
<h2>Answer:The number of milk chocolates are 18 and the number of dark chocolates are 24.</h2>

Step-by-step explanation:

Let the number of milk chocolates be m.

Let the number of dark chocolates be d.

Given that the box contains the milk and dark chocolates in the ratio 3:4.

So,\frac{m}{d}=\frac{3}{4}               ...(i)

Given that the total number of chocolates are 42.

So,m+d=42.                                   ...(ii)

Using (i) and (ii),

m+\frac{4}{3}m=42

\frac{7}{3}m=42

m=18

d=\frac{4}{3}m=\frac{4}{3}\times 18=24

So,the number of milk chocolates are 18 and the number of dark chocolates are 24.

4 0
3 years ago
Based on experience, the Ball Corporation’s aluminum can manufacturing facility in Ft. Atkinson, Wisconsin, knows that the metal
Veronika [31]

Answer:

a) 3.128

b) Yes, it is an outerlier

Step-by-step explanation:

The standardized z-score for a particular sample can be determined via the following expression:

z_i = {x_i -\bar x}/{s}

Where;

\bar x = sample means

s = sample standard deviation

Given data:

the mean shipment thickness (\bar x) = 0.2731 mm

With the standardized deviation (s) = 0.000959 mm

The standardized z-score for a certain shipment with a diameter x_i= 0.2761 mm can be determined via the following previous expression

z_i = {x_i -\bar x}/{s}

z_i = {0.2761-0.2731}/{ 0.000959}

z_i = 3.128

b)

From the standardized z-score

If [z_i < 2]; it typically implies that the data is unusual

If [z_i > 2]; it means that the data value is an outerlier

However, since our z_i > 3 (I.e it is 3.128), we conclude that it is an outerlier.

6 0
2 years ago
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