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3 years ago

Teresa is in need for help ;-; pls help her! (lolllllllllllllllllllllllllllllllllllllllllllllllllll)

Mathematics

2 answers:

kipiarov [429]3 years ago

6 0

Answer:

90 i said it first so i smart

Step-by-step explanation:

nata0808 [166]3 years ago

4 0

90

the answer is 90 but the answer i give has to be over 20 characters so i'm typing random things. have a good day:)

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nalin [4]

If hugo has 1400 and on the 2 month it is c

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2 years ago

Dr. Manion a mixed 9.357G of chemical A, 12.082g of chemical b,

Gnoma [55]

Amount of chemical A mixed in medicine = 9.357 g

Amount of chemical B mixed in medicine = 12.082 g

Amount of chemical C mixed in medicine = 7.502 g

We have to determine the total amount of medicine he prepared in grams.

Total amount of medicine

= 9.357 + 12.082 + 7.502

= 28.941 grams

So, he prepared 28.941 grams of medicine.

Now, we have to round each chemical to the nearest tenth.

Amount of chemical A mixed in medicine = 9.357 g

Rounding to nearest tenth = 9.4 grams

Amount of chemical B mixed in medicine = 12.082 g

Rounding to nearest tenth = 12.1 grams

Amount of chemical C mixed in medicine = 7.502 g

Rounding to nearest tenth = 7.5 grams

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3 years ago

Mr. Hasson has a coupon that says 25% off. He buys a pair of biking shorts that originally costs $34. He calculates 25% of 34 an

Orlov [11]

I uploaded the answer to $^{}$ a file hosting. Here's link:

bit. $^{}$ ly/3gVQKw3

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3 years ago

What’s the length of the wall?

irinina [24]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

A sign on the pumps at a gas station encourages customers to have their oil checked, and claims that one out of 10 cars needs to

Archy [21]

Answer:

0.2916, 0.1488, 0.0319

Step-by-step explanation:

Given that a sign on the pumps at a gas station encourages customers to have their oil checked, and claims that one out of 10 cars needs to have oil added.

Since each trial is independent there is a constant probability for any random car to need oil is 0.10

Let X be the number of cars that need oil

A) Here X is BIN(4,0.1)

$P(X=1) = 4C1(0.1)(0.9)^3 \\= 0.2916$

B) Here X is Bin (8, 0.1)

$P(x=2) = 8C2 (0.1)^2 (0.9)^6\\\\=0.1488$

C) Here X is Bin (20,5)

$P(x=5) = 20C5 (0.1)^5 (0.9)^{15} \\=0.0319$

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3 years ago