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stepladder [879]
3 years ago
7

What is the rate of change for the sequence shown below. (1,2) (2,2.5) (3,3) (4,3.5) (5,4)

Mathematics
1 answer:
Nataly [62]3 years ago
5 0

Answer:

0.5

Step-by-step explanation:

The given ordered pairs are: (1,2) (2,2.5) (3,3) (4,3.5) (5,4)

The corresponding sequence is :

2,2.5,3,3.5, 4,....

We can see that there is a common difference of d=0.5.

Better still we could use the slope formula:

m =  \frac{y_2-y_1}{x_2-x_1}

We substitute the point (1,2) and (2,2.5).

The rate of change of this sequence is:

m =  \frac{2.5 - 2}{2 - 1}  =  \frac{0.5}{1}  = 0.5

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Find the mean for the data set. {222, 240, 220, 234, 202, 244, 226, 226, 214, 215, 196, 210, 191, 220, 225, 210, 229, 200, 236,
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Answer:

answer

Step-by-step explanation:

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2 years ago
What is the common difference for this arithmetic sequence?54,50,46,42,38,...​
drek231 [11]

Answer:

Minus each number to figure out the common difference which is -4.

54-4= 50

50-4= 46

46-4= 42

42-4= 38

3 0
3 years ago
Three is what percent of eight
svet-max [94.6K]

Answer:

Step-by-step explanation:

x% of 8 = 3

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3 0
3 years ago
2x-10/4=3x<br> −10<br> −1<br> 2<br> 11
evablogger [386]

Answer:

<h2>-1</h2>

Step-by-step explanation:

\dfrac{2x-10}{4}=3x\qquad\text{multiply both sides by 4}\\\\2x-10=12x\qquad\text{subtract}\ 2x\ \text{from both sides}\\\\-10=10x\qquad\text{divide both sides by 10}\\\\-1=x\to x=-1

6 0
3 years ago
What is one of the solutions to the following equations? y2+x2=53<br> Y-x=5
Olenka [21]
(1)  y² + x² = 53
(2)  y - x = 5 ⇒ y = x + 5

subtitute (2) to (1)

(x + 5)² + x² = 53      |use (a + b)² = a² + 2ab + b²

x² + 2x·5 + 5² + x² = 53

2x² + 10x + 25 = 53     |subtract 53 from both sides

2x² + 10x - 28 =0     |divide both sides by 2

x² + 5x - 14 = 0

x² - 2x+ 7x - 14 = 0

x(x - 2) + 7(x - 2) = 0

(x - 2)(x + 7) = 0 ⇔ x - 2 = 0 or x + 7 = 0 ⇔ x = 2 or x = -7

subtitute the values of y to (2)

for x = 2, y = 5 + 2 = 7
for x = -7, y = 5 + (-7) = 5 - 2 = 3

Answer: x = 2 and y = 7 or x = -7 and y = 3
4 0
3 years ago
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