3 years ago

What is the function rule for the graph below?

Mathematics

1 answer:

11Alexandr11 [23.1K]3 years ago

6 0

Y= -x^2+4

B is the answer

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What is value of x?<br> Enter your answer in the box.

marin [14]

Answer:

$x \ = \ 10$

Step-by-step explanation:

Let point $D$ be the point where the straight line drawn from point $A$ meets the straight line $BC$ , it is evident that $\triangle ABD$ and $\triangle ACD$ is similar given that both triangles share the same angle, $\angle BAD \ = \ \angle DAC$ . Hence, the ratio of the sides of each triangle is the same. Specifically,

$\displaystyle{\frac{x+4}{8} \ = \ \frac{2x+1}{12}}$ .

Performing cross multiplication yields

$12\left(x+4\right) \ = \ 8\left(2x+1\right) \\ \\ \rule{0.15cm}{0cm}12x+48 \ = \ 16x+8 \\ \\ \rule{1.1cm}{0cm} 4x \ = \ 40 \\ \\ \rule{1.3cm}{0cm} x \ = \ 10$ .

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1 year ago

Which graph represents a function that is decreasing at a nonconstant rate?

Tasya [4]

Answer: C

since the line isn't straight, the slope/function is decreasing but not at a constant rate

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3 years ago

ASAP!! Please help me. I will not accept nonsense answers, but will mark as BRAINLIEST if you answer is correctly with solutions

Anarel [89]

Answer:

Step-by-step explanation:

Line of symmetry

4 0

3 years ago

You invest $9000 with a 6% interest rate compounded semiannually. After 9 yrs, how much money is in your account?

astraxan [27]

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$9000\\
r=rate\to 6\%\to \frac{6}{100}\to &0.06\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2\\

t=years\to &9
\end{cases}
\\\\\\
A=9000\left(1+\frac{0.06}{2}\right)^{2\cdot 9}$

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3 years ago

What is 298366366×874652882÷727+66377277×863663761-76544

pav-90 [236]

Answer:

5.7686613e+16

Step-by-step explanation:

Use PEMDAS, or the orders of operations, to solve this question.

3 0

3 years ago

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