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3 years ago

Help I need to correct this

Mathematics

1 answer:

Levart [38]3 years ago

4 0

I believe B,C, and D is correct...

please vote my answer brainliest. thanks!

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15. Solve the compound inequality.<br> 5x - 11 < -11 or 4x + 2 > 14

s2008m [1.1K]

Answer:

Step-by-step explanation:

5x −11+11<-11+11

5x<0

5x/5<0/5

x<0

4x+2 -2 >14 -2

4x>12

4x/4>12/4

x>3

there both open not closed

hope this helps

5 0

3 years ago

Destiny has 10$ and Elijah has 5$. I give each person the same amount of money each week. This situation can be represented with

Darina [25.2K]

Answer:

I do believe that the answer is 0 solutions.

Step-by-step explanation:

x+10 =x+5

Subtract 5 from both sides, you get:

x+5=x

Subtract x from both sides, and you get:

5=0 which is NOT true. Also I maybe wrong, pls don't be mad at me.

8 0

2 years ago

Solve 2cos^2x + cosx − 1 = 0 for x over the interval [0, 2 π ).

alina1380 [7]

Let cos x = a, then
2a^2 + a - 1 = 0,
solving the quadratic equation, we have:
a = 0.5 or -1.

i.e. cos x = 0.5 or cos x = -1
for cos x = 0.5,
x = pi/3, 2pi - pi/3 = pi/3, 5pi/3

for cos x = -1,
x = pi

therefore, x = pi, pi/3, 5pi/3
Answer: B

6 0

3 years ago

When fishing off the shores of Florida, a spotted seatrout must be between 10 and 30 inches long before it can be kept; otherwis

Mademuasel [1]

Answer:

There is a 97.585% probability that a fisherman catches a spotted seatrout within the legal limits.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

In this problem, we have that:

The lengths of the spotted seatrout that are caught, are normally distributed with a mean of 22 inches, and a standard deviation of 4 inches, so $\mu = 22, \sigma = 4$ .