To get t on one side, we have to use inverse operations to get rid of the 5.
1. Use inverse operation of multiplication to get rid of 5. Which would be division.
2. Divide both sides by 5.
5t/5 = 7 1/2 / 5
3. Solve.
5t/5 = t and 7 1/2 /5 = 1 1/2
7.5 / 5 = 1.5
Therefore, your answer would be C. divide both sides by 5, and the answer is 1 1/2.
Answer:
9² = 81
-5⁴ = -625
- 3⁴ = - 81
¼³ = 0.015625
Step-by-step explanation:
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Answer:
28.26
Step-by-step explanation:
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Answer:
Yes the probability of getting at least one airplane from two boxes is 3/4 which is greater than 0.5.
Step-by-step explanation:
The probability of getting at least one aeroplane is calculated by = 1 -(P(not aeroplane from 1st box) P (not aeroplane from 2nd box))
P(at least one aeroplane)= 1- {P(not aeroplane)P(not aeroplane)}
Suppose there is one helicopter and one aeroplane in each box so
P(at least one aeroplane)= 1- {(1/2) (1/2))}
P(at least one aeroplane)= 1- 1/4
P(at least one aeroplane)= 3/4 > 0.5
So the probability of getting at least one airplane from two boxes is 3/4 which is greater than 0.5
Step-by-step explanation:
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