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Ray Of Light [21]
3 years ago
10

What would indicate that a physical change takes place when copper is drawn into wire? Copper is heated, changing its molecular

structure. Copper is reshaped, but its molecular structure does not change. A new substance is formed that helps in drawing copper wire. Copper changes its color when drawn into wire.
Chemistry
2 answers:
egoroff_w [7]3 years ago
7 0
Copper is reshaped, but it's molecular structure does not change. So B.
motikmotik3 years ago
4 0
Copper is reshaped, but its molecular structure does not change.
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How many moles would there be in 1.5x10^24 molecules of water?
Nookie1986 [14]

Answer:

5.85 moles

Explanation:

Moles in (3.52 X 10^24) molecules of water. 3.52 x 10^24 molecules x `1mol/6.02 x 10^23 molecules = 5.85 moles of H2O.

3 0
3 years ago
Is a blender (at home) an example of electrical to mechanical energy? If so, why? Please explain thoroughly
san4es73 [151]

Answer:

Yes it is

Explanation:

You use electricity to power the blender itself, then after you power it the potential energy becomes kinetic energy which equals mechanical energy in the blender. So yes, a blender is an example of electrical to mechanical energy.

6 0
3 years ago
An unknown metal sample has a mass : of 11.29. and a volume of 2 cm3. What is the : density of the unknown metal? ​
tatuchka [14]

Answer:

\boxed{\sf Density \ of \ the \ unknown \ metal = 5.645 \ g/cm^3}

Given:

Mass = 11.29 g

Volume = 2 cm³

To Find:

Density of unknown metal

Explanation:

Formula:

\boxed{ \bold{Density = \frac{Mass}{Volume}}}

Substituting value of mass & volume in the formula:

\sf \implies Density =  \frac{11.29}{2} \\  \\   \sf \implies Density =  5.645 \: g/cm^3

3 0
3 years ago
How many moles of Boron are present in 20g of borax (sodium tetraborate)?​
stira [4]
20 grams of borax contains (20.0g) / (201 g mol -1) =0.10 mol of borax.

Therefore 0.40 mol of borax
5 0
3 years ago
Problem PageQuestion A student prepares a aqueous solution of butanoic acid . Calculate the fraction of butanoic acid that is in
Yanka [14]

Answer:

Incomplete question: A student prepares a 0.54 mM aqueous solution of butanoic acid...

The answer is: The percentage of dissociation is 15.4%

Explanation:

Given:

Ka = 1.51x10⁻⁵

Concentration = 0.54 mM = 0.54x10⁻³M

The reaction is:

                   C₄H₈O₂               =             C₄H₇O₂⁻          +           H⁺

I                    0.54x10⁻³                             0                                0

E                   0.54x10⁻³(1-x)                      0.54x10⁻³x                0.54x10⁻³x

Where x is the degree of dissociation

Ka=\frac{[H^{+}][C_{4}H_{7}O_{2}^{-}     }{[C_{4}H_{8}O_{2}   } \\1.51x10^{-5} =\frac{0.54x10^{-3}x^{2}  }{1-x} \\x^{2} +0.028x-0.028=0\\x_{1} =0.154\\x_{2} =-0.182

We will choose the positive value

x = 0.154

The percentage of dissociation is 15.4%

3 0
3 years ago
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