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olga nikolaevna [1]
1 year ago
7

In three to five sentences, list examples of renewable and nonrenewable energy sources. Then compare and contrast the energy sou

rces in terms of environmental impact.
Chemistry
1 answer:
Digiron [165]1 year ago
3 0

Resources can be renewable or nonrenewable based on their replenishing power. Some renewable energy sources are wind, water, and solar energy, and nonrenewable is natural gas, coal, diesel, etc.

<h3>What are renewable and non-renewable sources?</h3>

Renewable resources are the things that can get refilled when they are utilized for the purpose. Nonrenewable resources are the sources that have a short existing period of life.

Some examples of renewable resources are wind, air, groundwater, solar energy, timber, soil, etc. Some nonrenewable resources are coal, petrol, diesel, natural gas, etc.

Renewable resources are present for an infinite time period while the non-renewable get depleted when excessively used. Renewable has less environmental impact than nonrenewable sources as they lack harmful chemicals that causes the environmental imbalance.

Therefore, nonrenewable resources are harmful to the environment compared to renewable resources.

Learn more about nonrenewable resources here:

brainly.com/question/4406961

#SPJ1

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1‑propanol ( n ‑propanol) and 2‑propanol (isopropanol) form ideal solutions in all proportions. Calculate the partial pressure a
Alex777 [14]

Answer:

y_{prop} = 0.134; y_{iso} = 0.866

The partial pressure of isopropanol = 34.04 Torr; The partial pressure of propanol = 5.26 Torr

Explanation:

For each of the solutions:

mole fraction of isopropanol  (x_{iso}) = 1 - mole fraction of propanol (x_{prop}).

Given: mole fraction of propanol = 0.247. Thus, the mole fraction of isopropanol = 1 - 0.247 = 0.753.

Furthermole, the partial pressure of isopropanol = x_{iso}*vapor pressure of isopropanol = 0.753*45.2 Torr = 34.04 Torr

The partial pressure of propanol = x_{prop}*vapor pressure of propanol = 0.247*20.9 Torr = 5.16 Torr

Similarly,

In the vapor phase,

The mole fraction of propanol (y_{prop}) = \frac{P_{prop} }{P_{prop}+P_{iso}}

Where, P_{prop} is the partial pressure of propanol and P_{iso} is the partial pressure of isopropanol.

Therefore,

y_{prop} = 5.26/(34.04+5.16) = 0.134

y_{iso} = 1 - 0.134 = 0.866

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