3 years ago

What would happen if carbon -14 gained 1 proton and lost 1 neutron?

1 answer:

4 0

D. To answer this question refer to the periodic table and think logically about it. Adding one proton increases the atomic number so you go along the row to Nitrogen. If you lose one neutron then the atomic mass decreases by 1 so 14-1 is 13.

You might be interested in

If the volume of a gas at 0.5 atm changes from 150 mL to 75 mL, what is the new pressure?

prisoha [69]

Answer:

Explanation:

The new pressure can be found by using the formula for Boyle's law which is

$P_1V_1 = P_2V_2$

Since we're finding the new pressure

$P_2 = \frac{P_1V_1}{V_2} \\$

We have

$P_2 = \frac{0.5 \times 150}{75} = \frac{75}{75} = 1 \\$

We have the final answer as

Hope this helps you

5 0

3 years ago

____N2 + ____H2  ____NH3

Fiesta28 [93]

Answer:

N2 + 3H2 + 2NH3

Explanation:

I'm assuming you're balancing the chemical equation

3 0

2 years ago

Read 2 more answers

A double replacement reaction is a reaction in which one element replaces a similar element within a compound. (2 points)

emmainna [20.7K]

Answer:

False

Explanation:

youre welcome

3 0

3 years ago

U/d21/ms/quizzing/user/attempt/quiz_start_frame_auto.d2l?u=2332447&isprv=&dic=0&q=2942919do

Masteriza [31]

Answer:

876 grams

Explanation:

Convert specific gravity to density, using water density 1.0 g/ml

d = e.g x 1.0 g/ml = 1.168 g/ml

d = m/v (mass/volume)

m = dxv = 1.168 g/ml x 750 ml = 876 grams

4 0

3 years ago

What is the concentration of hydroxide in a solution with a pOH of 9.8?

eimsori [14]

Answer:

1.6*10^(-10) M

Explanation:

pOH = 9.8

[OH-]=10^{-log(pOH)} = 10^(-9.8) = 1.6*10^(-10)

6 0

3 years ago