Answer:
(12,-6)
Step-by-step explanation:
we have
----> inequality A
---> inequality B
we know that
If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities (makes true both inequalities)
<u><em>Verify each point</em></u>
Substitute the value of x and the value of y of each ordered pair in the inequality A and in the inequality B
case 1) (0,-1)
Inequality A
----> is true
Inequality B
----> is not true
therefore
The ordered pair is not a solution of the system
case 2) (0,3)
Inequality A
----> is true
Inequality B
----> is not true
therefore
The ordered pair is not a solution of the system
case 3) (-6,-6)
Inequality A
----> is true
Inequality B
----> is not true
therefore
The ordered pair is not a solution of the system
case 4) (12,-6)
Inequality A
----> is true
Inequality B
----> is true
therefore
The ordered pair is a solution of the system (makes true both inequalities)
Answer:
x=10 x=-4
Step-by-step explanation:
x^2 +6x = 40
subtract 40 from each side
x^2 +6x -40 = 0
what numbers multiply to -40 and add to 6
-10 *4 = -40 -10 +4 = 6
(x-10) (x+4) = 0
using the zero product property
x-10 = 0 x+4 =0
x=10 x=-4
Square when you look at the graphed answer
Answer:
Population Of the United States
Weight of a small car
Length of a bed
Weight of an average man