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mina [271]
9 months ago
11

Detmermine the best method to solve the following equation, then solve the equation. (3x-5)^2=-125

Mathematics
1 answer:
liq [111]9 months ago
3 0

For the given equation;

(3x-5)^2=-125

We shall begin by expanding the parenthesis on the left side, after which we would combine all terms on and move all of them to the left side, which shall yield a quadratic equation. Then we shall solve.

Let us begin by expanding the parenthesis;

\begin{gathered} (3x-5)^2\Rightarrow(3x-5)(3x-5) \\ (3x-5)(3x-5)=9x^2-15x-15x+25 \\ (3x-5)^2=9x^2-30x+25 \end{gathered}

Now that we have expanded the left side of the equation, we would have;

\begin{gathered} 9x^2-30x+25=-125 \\ \text{Add 125 to both sides and we'll have;} \\ 9x^2-30x+25+125=-125+125 \\ 9x^2-30x+150=0 \end{gathered}

We shall now solve the resulting quadratic equation using the quadratic formula as follows;

\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ \text{Where;} \\ a=9,b=-30,c=150 \\ x=\frac{-(-30)\pm\sqrt[]{(-30)^2-4(9)(150)}}{2(9)} \\ x=\frac{30\pm\sqrt[]{900-5400}}{18} \\ x=\frac{30\pm\sqrt[]{-4500}}{18} \\ x=\frac{30\pm\sqrt[]{-900\times5}}{18} \\ x=\frac{30\pm\sqrt[]{-900}\times\sqrt[]{5}}{18} \\ x=\frac{30\pm30i\sqrt[]{5}}{18} \\ \text{Therefore;} \\ x=\frac{30+30i\sqrt[]{5}}{18},x=\frac{30-30i\sqrt[]{5}}{18} \\ \text{Divide all through by 6, and we'll have;} \\ x=\frac{5+5i\sqrt[]{5}}{3},x=\frac{5-5i\sqrt[]{5}}{3} \end{gathered}

ANSWER:

x=\frac{5+5i\sqrt[]{5}}{3},x=\frac{5-5i\sqrt[]{5}}{3}

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Step-by-step explanation:

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The rectangle below has an area of x^2-7x+10square meters and a width of x - 5 meters. What expression represents the length of
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Answer:

L = (x - 2) meters

Step-by-step explanation:

The area of the rectangle = (x² - 7x + 10) m²

The width = (x - 5) m

length = ?

Area of a rectangle = length × width

x² - 7x + 10 = L(x -5)

note L = length

divide both sides by (x-5)

(x² - 7x + 10)/(x - 5) = L

L = x² - 7x + 10 / (x -5)

Factorize x² - 7x + 10

find the numbers you can multiply to give you 10 and also add to give you -7

The numbers are -2 and -5. Therefore,

x² - 2x - 5x + 10 = 0

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Let us go back to our division

L = x² - 7x + 10 / (x -5)

x² - 7x + 10 = (x-5)(x-2)

L = (x-5)(x-2) / (x -5)

L = (x - 2) meters

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What is the slope of the line that passes through the points (-3, 5) and (1, 7)?
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\bf (\stackrel{x_1}{-3}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{7}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{7-5}{1-(-3)}\implies \cfrac{7-5}{1+3}\implies \cfrac{2}{4}\implies \cfrac{1}{2}

4 0
2 years ago
Read 2 more answers
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