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I am Lyosha [343]
3 years ago
5

Subtract and simplify (y^2 – 3y – 5) - (-y^2 – 7y+4)

Mathematics
1 answer:
polet [3.4K]3 years ago
7 0
It would be 2y^2+4y-9
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Solve 4x2-25&lt;0<br><br> in words 4x squared -minus 25 &lt; 0
muminat
<h3>I'll teach you how to solve 4x^2-25<0</h3>

-------------------------------------------------

4x^2-25<0

Add 25 to both sides:

4x^2-25+25 < 0+25

Simplify:

4x^2 < 25

Divide both sides by 4:

4x^2/4 < 25/4

Simplify:

x^2 < 25/4

whole sqrt -25/4 < x < whole sqrt 25/4

whole sqrt 25/4= 5/2

-5/2 < x < 5/2

Your Answer Is -5/2 < x < 5/2

plz mark me as brainliest if this helped :)

4 0
3 years ago
Use the interactive graph to plot each set of points which set represents proportional relationships check all that apply
Afina-wow [57]

Answer:

the first and third

Step-by-step explanation:

6 0
3 years ago
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How do I solve this .... question in the image. <br><br>thank you​
dezoksy [38]

Answer:

Below

Step-by-step explanation:

● x-20 = y+20 (1)

● 2(y-22) = x+22 (2)

This is a system of simulataneous equations

Let's simplify the expressions first

● x -20 = y + 20 (1)

Add 20 to both sides

● x -20 + 20 = y+20 +20

● x = y + 40 (1)

● 2(y-22) = x+22 (2)

● 2y - 44 = x +22

Substrat 22 from both sides

● 2y-44-22 = x+22-22

● 2y -66 = x (2)

This is the new system:

● x = y+40 (1)

● x = 2y-66 (2)

Substract (2) from (1)

● x-x = y+40-(2y-66)

● y+40-2y+66 = 0

● -y +106 = 0

● y = 106

Replace y with 106 in (1)

● x = y +40

● x = 106+40

● x = 146

So the solutions are (146,106)

8 0
3 years ago
According to records in a large hospital, the birth weights of newborns have a symmetric and bell-shaped relative frequency dist
Kamila [148]

Answer:

15.9% of babies are born with birth weight under 6.3 pounds.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 6.8 pounds

Standard Deviation, σ = 0.5

We are given that the distribution of  birth weights is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(birth weight under 6.3 pounds)

P(x < 6.3)

P( x < 6.3) = P( z < \displaystyle\frac{6.3 - 6.8}{0.5}) = P(z < -1)

Calculation the value from standard normal z table, we have,  

P(x < -1) = 0.159 = 15.9\%

15.9% of babies are born with birth weight under 6.3 pounds.

8 0
3 years ago
. Add 91, 129, and 16, and then divide by 44
irga5000 [103]

Answer: 5.36363636364

Step-by-step explanation:

91+ 129+ 16=236

236 ÷44= 5.36363636364

3 0
3 years ago
Read 2 more answers
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