Answer:
32 seconds
Step-by-step explanation:
For some number of seconds (s), Tess's essay length (t) will be ...
t = 42 +1.3s
and Margo's essay length (m) will be ...
m = 122 -1.2s
We will have t > m when ...
t > m
42 +1.3s > 122 -1.2s
2.5s > 80 . . . . . . . . add 1.2s-42
s > 32 . . . . . . . . . . . divide by 2.5
After 32 seconds, Tess's essay will exceed Margo's in length.
Answer:
45
Step-by-step explanation:
Evaluate 5 x^2 - 3 (x - 2) + x where x = 3:
5 x^2 - 3 (x - 2) + x = 5×3^2 - 3 (3 - 2) + 3
3^2 = 9:
5×9 - 3 (3 - 2) + 3
3 - 2 = 1:
5×9 - 3 + 3
5×9 = 45:
45 - 3 + 3
45 + 3 = 48:
48 - 3
| 4 | 8
- | | 3
| 4 | 5:
Answer: 45
Answer:
482
Step-by-step explanation:
We can see that the numbers shown resemble an arithmetic sequence because they have a common difference. The formula for the nth term of an arithmetic sequence is:
Where 
is the first term, 
is the nth term, and 
is the common difference. To find the 61st term, all we need is the first term and the common difference. By looking at what given, we can say the first term is 2. Now, to find the common difference, we find the difference of a term from the term before it. In this case we can do 
, which is 
, or the common difference. Since we have everything we need, it can be plugged into the equation:
So, the 61st term is 482.
