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Contact [7]
3 years ago
6

4d to the third power-10 in verbal expression

Mathematics
1 answer:
laiz [17]3 years ago
6 0
Four times a number d cubed minus ten.  (cubed means to the 3rd power)
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Which of the following is in Integrity but not a whole number A -9.6 B -4 ​
abruzzese [7]

Answer:

B. -4.

Step-by-step explanation:

3 0
2 years ago
An accounting machine operator wanted to divide an 85-minute job between two identical machines so that one machine would take o
Lubov Fominskaja [6]
To find how much time the machine that took the longer job is, you would create an equation in terms of X, the amount of time it takes one of the machines.

Please see the attached picture for the work.

51 minutes is the longer time.
34 minutes for the other machine.

6 0
3 years ago
Can someone please explain step by step on this problem for a brainliest!
Shkiper50 [21]

Answer:

Combine the like terms. In this equation there are two like terms. They both are xy. Note: When there is no number in front of a term, you can assume that the number is 1.

5xy - 1xy

Subtract normally and then attach the xy.

4xy

Hope this helps! :)

7 0
2 years ago
Read 2 more answers
The diameter of a circle has endpoints P(-6,-11 ) and Q(4, 7). Write an equation for the circle. Be sure to show and explain all
MrMuchimi

Answer:

(x + 1)^2 + (y + 2)^2 = 106

Step-by-step explanation:

The formula for a circle is

(x - h)^2 + (y - k)^2 = r^2

Where (h, k) is the center of the circle and r is the raadius

--------------------------------------

The center is the midpoint of the diameter end points

(h, k) = ( (-6 + 4)/2 , (-11 + 7)/2 )

(h, k) = (-1, -2)

The radius is the distance from the center to an endpoint

Using (h, k) and Q

r^2 = (4 - -1)^2 + (7 - -2)^2

r^2 = 5^2 + 9^2

r^2 = 106

-------------------------------

Plug into the circle formula

(x + 1)^2 + (y + 2)^2 = 106

7 0
3 years ago
Find the cardinal number for the set. Α = {3, 6, 9, . . . , 36}
Elena-2011 [213]

<em>Hey </em><em>mate!</em><em>!</em>

<em>Answer:</em>

<em>n(</em><em>A)</em><em>=</em><em>1</em><em>2</em>

<em>Solution</em><em>,</em>

<em>A=</em><em>{</em><em>3</em><em>,</em><em>6</em><em>,</em><em>9</em><em>,</em><em>1</em><em>2</em><em>,</em><em>1</em><em>5</em><em>,</em><em>1</em><em>8</em><em>,</em><em>2</em><em>1</em><em>,</em><em>2</em><em>4</em><em>,</em><em>2</em><em>7</em><em>,</em><em>3</em><em>0</em><em>,</em><em>3</em><em>3</em><em>,</em><em>3</em><em>6</em><em>}</em>

<em>Just </em><em>count </em><em>the </em><em>elements</em><em>,</em>

<em>There </em><em>are </em><em>1</em><em>2</em><em> </em><em>elements </em><em>in </em><em>the </em><em>set.</em>

<em>So </em><em>the </em><em>cardinal </em><em>number </em><em>of </em><em>the </em><em>set </em><em>is </em><em>1</em><em>2</em><em>.</em>

<h2><em>Hope </em><em>it </em><em>helps.</em><em>.</em><em>.</em></h2>
8 0
3 years ago
Read 2 more answers
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