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madreJ [45]
3 years ago
11

3+7x<26 help me with this equaton

Mathematics
1 answer:
Vadim26 [7]3 years ago
7 0
3+ 7x < 26
-3 -3

7x < 23

divide by 7 to isolate x (variable)

x< 7/23 final answer

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4.5w = 5.1w - 30<br><br> Please help!!!
Lelu [443]
4.5w = 5.1w - 30

4.5w - 5.1w = -30

-0.6w =-30

Divide both sides by -0.6

-0.6w/-0.6 = -30/-0.6

<span>w = 50

</span>I hope this helps.
6 0
4 years ago
What is the arithmetic sequence of a1=228 n=28 sn=2982
Art [367]

Answer:

use the formula sn= n(a1+an)/2

Step-by-step explanation:

2982=28(228+an)/2

5964=28(228+an)

5964/28=228+an

213=228+an

an=-15(last term)

to find difference use formula

an = a+(n-1)d

-15=228+(28-1)d

-243=27d

d=-243/27

d=-9

arithmetic sequence  can be found be keep on subtracting 9 from 228

hence the arithmetic sequence is

228, 219, 210, 201, 192, 183, 174........-15

3 0
3 years ago
Goose had 5 hens Xhicken took two how many is left?
scoray [572]

Answer:

3

Step-by-step explanation:

why would a goose have hens

6 0
2 years ago
Shishir bought 4000 orange at 70 paisa each. But 400 of them were rotten. He sold 2000 oranges at 90 paisa each.If he plans to m
Ipatiy [6.2K]

Answer:

He needs to sell the rest of the oranges at 75 paisa each.

Step-by-step explanation:

Consider the given information that, Shishir bought 4000 orange at 70 paisa each.

Note: 1 rupees = 100 paisa

Thus, 70 paisa = 70/100 rupees = 0.70 rupees

Therefore, the cost price of 4000 oranges is:

4000×0.70 rupees = 2800 rupees

The selling price of 2000 oranges is:

2000×0.90 rupees = 1800 rupees

The number of oranges now Shishir have:

4000 - 2000 - 400 = 1600

He wants to make a profit of RS 200. Thus the selling price of 4000 oranges should be:

2800 rupees + 200 rupees = 3000 rupees

He earned 1800 rupees by selling 2000 oranges at 90 paisa. So, the remaining amount that he needs to make with 1600 oranges is:

3000 rupees - 1800 rupees = 1200 rupees

Therefore, the cost of one orange is:

1600 oranges = 1200 rupees

1 orange = 1200/1600 rupees

1 orange = 0.75 rupees

Hence, he needs to sell the rest of the oranges at 75 paisa each.

4 0
3 years ago
A positive integer is 5more than 23 times another. Their product is 6732. Find the two integers
aliina [53]

One integer is m.

The other integer is n.


n = 23m + 5

mn = 6732


m = 6732/n


n = 23 * 6732/n + 5


n = 154,836/n + 5


n^2 = 154,836 + 5n


n^2 - 5n - 154,836 = 0


n = [5 +- sqrt(25 + 4 * 154,836)]/2


n = (5 +- 787)/2


n = 396 or n = -391


We discard -391 because the problem is looking for positive integers.


mn = 6732


m = 6732/n = 6732/396


m = 17


Answer: The integers are 17 and 396.

3 0
3 years ago
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