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krek1111 [17]
4 years ago
5

Use ABC, in which AB = 48, AC = 64, and BC = 80, to answer the question.

Mathematics
1 answer:
Deffense [45]4 years ago
4 0

Answer:

CosB  = \frac{48}{80}

Step-by-step explanation:

Given

AB = 48, AC = 64, and BC = 80

Required

Determine the ratio of cosB

The first step is to determine, which type of triangle it is.

Checking for Right Angled Triangle

For a triangle to be a right angled triangle, the square of the largest side must be equal to the sum of squares of other sides

This implies that:

80^2 = 48^2 + 64^2

6400 = 2304 + 4096

6400 = 6400

<em>Hence, the triangle is a right angled triangle [See attachment]</em>

From trigonometry;

CosB  = \frac{Adjacent}{Hypotenuse}

The adjacent of B = 48 while the hypotenuse is 80;

Hence;

CosB  = \frac{48}{80}

Hence, the ratio of cos B is CosB  = \frac{48}{80}

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For the circle, we know that 4/5 and 1/10 is fit. Now we need the last one, to solve, we need to get the same denominator and see how much is missing.

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2

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Answer:

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