Given f(x) = √(x-3) , what is the positive value of f(12)?

Mathematics

1 answer:

Shalnov [3]4 years ago

6 0

Answer:

Step-by-step explanation:

Given

f(x) = $\sqrt{(x-3)}$ , then

f(12) = $\sqrt{12-3}$ = $\sqrt{9}$ = ± 3

There are 2 values 3 and - 3

The positive value of f(12) is + 3

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Tan(-212°)=____. 1. -cot 32° 2. tan 32° 3. cot 32° 4. -tan 32°

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Answer:

4. $-\tan 32$ °

Step-by-step explanation:

Given:

The tangent of the angle is given as:

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Since the angle is negative, it means that it is measured in the clockwise direction as angles measured in clockwise direction are negative and that measured in counter clockwise directions are positive.

-212° when measured from counter clockwise direction will be equal to:

$-212\°(Clockwise)=360-212=148\°(CCW)$

Therefore, $\tan (-212\°)$ = $\tan (148\°)$

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$\tan(\pi-\theta)=-\tan \theta$

Here, $\theta=148\°$

Therefore,

$-\tan (148\°)=\tan(180-148)\\-\tan(148\°)=\tan(32\°)\\\textrm{Multiplying both sides by -1, we get:}\\-1(-\tan(148\°)=-1\times \tan(32\°)\\\\\tan(148\°)=-\tan(32\°)$