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2 years ago

Someone please help me

Mathematics

1 answer:

Troyanec [42]2 years ago

4 0

Pythagorean theorem is $a^{2} + b^{2} = c^{2}$
and using that sin is opposite/hypotenuse, you can find the third side of the triangle.
$11^{2}+(adjacent)^{2} = 61^{2} \\ 121+ (adjacent)^{2} = 3721 \\ (adjacent)^{2}=3600 \\ adjacent = 60$
now you know adjacent is 60, so cos=60/61

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Evaluate The Following Expression When X= -5 <br> -4+3-(2x+5)²

andriy [413]

Answer:

-26

Step-by-step explanation:

sub in the x value

-4+3-(2(-5)+5)^2

-4+3-(-10+5)^2

-4+3-(5)^2

-1-25

-26

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2 years ago

Simplify the expression 4x+10+6x+2x

il63 [147K]

Answer:

12X+10

Step-by-step explanation:

It's easy. Just combine like terms. Like terms must have the same variable and to the same power in this case all the terms have a power of 1, but it doesnt show it because it doesn't really matter. So 4x,6x, and 2x all have the same variable so add them together. That gets you 10x. Since nothing else in the expression has the same variable with 10, you leave the 10 at the end resolving in 12x+10

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2 years ago

Read 2 more answers

Evaluate the numerical expression.<br>9x [(26-4)-(4+7)]<br>The value of the expression is

mash [69]

Answer:

Step-by-step explanation:

26-4=22. 4+7=11. 22-11=11. 9 times 11=99

6 0

3 years ago

Read 2 more answers

Determine the standard form of the equation of the line that passes through (6, -9) and (-8, 6)

horrorfan [7]

9514 1404 393

Answer:

A. 15x +14y = -36

Step-by-step explanation:

Since we are given two points, we can start with the 2-point form of the equation for a line.

y = (y2 -y1)/(x2 -x1)(x -x1) +y1

y = (6 -(-9))/(-8 -6)(x -6) +(-9)

y = 15/-14(x -6) -9

Multiplying by -14, we have ...

-14y = 15x -90 +126

Adding 14y-36 to both sides gives ...

-36 = 15x +14y . . . . matches choice A

The standard-form equation is ...

15x +14y = -36

_____

<em>Additional comments</em>

It can be easier to start with the form ...

(Δy)x -(Δx)y = (Δy)x1 -(Δx)y1 . . . . . where Δx = x2-x1 and Δy = y2-y1

This gives ...

(6+9)x -(-8-6)y = 15(6) +14(-9)

15x +14y = -36 . . . simplified

You can also start with the slope-intercept form or the point-slope form, if you're more familiar with those. The result will be the same. I find it handy to be familiar with a number of different forms of the equation for a line.

4 0

2 years ago

Find the product of following:(i) (x+3) (x+2) (ii) (2x-1) (2x-7)

Inga [223]

Part (i)

<h3>Answer: x^2 + 5x + 6</h3>

-----------------

Work Shown:

(x+3)(x+2)

y(x+2) ..... Let y = x+3

y*x + y*2 ... distribute

x(y) + 2(y)

x(x+3) + 2(x+3) .... plug in y = x+3

x*x + x*3 + 2*x + 2*3 ... distribute

x^2 + 3x + 2x + 6

x^2 + 5x + 6

=====================================================

Part (ii)

<h3>Answer: 4x^2 - 16x + 7</h3>

-----------------

Work Shown:

We could follow the same set of steps as shown back in part (i), but I'll show a different approach. Feel free to use the method I used back in part (i) if the visual approach doesn't make sense.

The diagram below is a visual way to organize all the terms. Many textbooks refer to it as "the box method" which helps multiply out any two algebraic expressions.

Each inner cell is found by multiplying the corresponding outer terms. For instance, in the upper left corner we have 2x*2x = 4x^2. The other cells are filled out the same way.

The terms in those four inner cells (gray boxes) are:

4x^2
-14x
-2x
7

The like terms here are -14x and -2x which combine to -16x, since -14+(-2) = -16.

We end up with the answer 4x^2-16x+7

8 0

2 years ago